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Get the maximum mark records from a collection with documents in MongoDB query
To get the maximum marks records, use sort() in descending order along with limit 1. Let us create a collection with documents −
> db.demo241.insertOne({"Marks":67}); { "acknowledged" : true, "insertedId" : ObjectId("5e441f729af932883c61ea40") } > db.demo241.insertOne({"Marks":89}); { "acknowledged" : true, "insertedId" : ObjectId("5e441f769af932883c61ea41") } > db.demo241.insertOne({"Marks":78}); { "acknowledged" : true, "insertedId" : ObjectId("5e441f789af932883c61ea42") }
Display all documents from a collection with the help of find() method −
> db.demo241.find();
This will produce the following output −
{ "_id" : ObjectId("5e441f729af932883c61ea40"), "Marks" : 67 } { "_id" : ObjectId("5e441f769af932883c61ea41"), "Marks" : 89 } { "_id" : ObjectId("5e441f789af932883c61ea42"), "Marks" : 78 }
Following is the query to get the maximum marks −
> db.demo241.find().sort({Marks:-1}).limit(1);
This will produce the following output −
{ "_id" : ObjectId("5e441f769af932883c61ea41"), "Marks" : 89 }
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