Find the following products:
$ \frac{-8}{27} x y z\left(\frac{3}{2} x y z^{2}-\frac{9}{4} x y^{2} z^{3}\right) $

AcademicMathematicsNCERTClass 8

Given:

\( \frac{-8}{27} x y z\left(\frac{3}{2} x y z^{2}-\frac{9}{4} x y^{2} z^{3}\right) \)

To do:

We have to find the given product.

Solution:

$\frac{-8}{27} x y z(\frac{3}{2} x y z^{2}-\frac{9}{4} x y^{2} z^{3})=\frac{-8}{27} x y z \times \frac{3}{2} x y z^{2}+(\frac{-8}{27} x y z) \times(\frac{-9}{4} x y^{2} z^{3})$

$=\frac{-4}{9} x^{1+1} y^{1+1} z^{1+2}+\frac{2}{3} x^{1+1} y^{1+2} z^{1+3}$

$=\frac{-4}{9} x^{2} y^{2} z^{3}+\frac{2}{3} x^{2} y^{3} z^{4}$

raja
Updated on 10-Oct-2022 13:19:29

Advertisements