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C++ Program to count square root cube root and both in given range
Suppose we have a number n. We have to count the number of integers x, in range 1 to n such that, that x is a square of a positive integer number or a cube of a positive integer number (or both a square and a cube simultaneously).
Problem Category
Various problems in programming can be solved through different techniques. To solve a problem, we have to devise an algorithm first, and to do that we have to study the particular problem in detail. A recursive approach can be used if there is a recurring appearance of the same problem over and over again; alternatively, we can use iterative structures also. Control statements such as if-else and switch cases can be used to control the flow of logic in the program. Efficient usage of variables and data structures provides an easier solution and a lightweight, low-memory-requiring program. We have to look at the existing programming techniques, such as Divide-and-conquer, Greedy Programming, Dynamic Programming, and find out if they can be used. This problem can be solved by some basic logic or a brute-force approach. Follow the following contents to understand the approach better.
So, if the input of our problem is like n = 25, then the output will be 6
Steps
To solve this, we will follow these steps −
a := square root of n b := cube root of n c := cube root of a return a + b - c
Example
Let us see the following implementation to get better understanding −
#include <bits/stdc++.h>
using namespace std;
int solve(int n){
int a = sqrt(n), b = cbrt(n), c = cbrt(a);
return a + b - c;
}
int main(){
int n = 25;
cout << solve(n) << endl;
}Input
25
Output
6
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