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# Construct a right triangle whose base is $ 12 \mathrm{~cm} $ and sum of its hypotenuse and other side is $ 18 \mathrm{~cm} $.

**Given:**

Base $=12\ cm$ and the sum of the hypotenuse and another side $=18\ cm$.

**To do:**

We have to construct the right triangle with the given measurements.

**Solution:**

Steps of construction:

(i) Let us draw the base $BC$ of length $12\ cm$.

(ii) Now, construct an angle $XBC$ such that $\angle XBC=90^o$ from point B.

(iii) Now, by taking the measure $18\ cm$ with the compasses let us draw an arc from point $B$ on the ray $BX$ and mark the point of intersection of the ray with the arc as $D$.

(iv) Let us now join $DC$. Now, draw a perpendicular bisector of the line $CD$ and mark the point of intersection of the bisector with the ray $BX$ as point $A$.

(v) Then join $AC$. Therefore the required right-angled triangle is formed.

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