Complete the entries in the third column of the table.
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AcademicMathematicsNCERTClass 6

To do:

We have to complete the entries in the third column of the given table.

Solutions:

(a) $10y = 80$

If $y = 10$ then $10y=10(10)=100$

$y=10$ is not a solution for the equation $10y = 80$ 

Therefore, the equation is not satisfied.

(b) $10y = 80$

If $y = 8$ then $10y=10(8)=80$

$y=8$ is a solution for the equation $10y = 80$ 

Therefore, the equation is satisfied.

(c) $10y = 50$

If $y = 5$ then $10y=10(5)=50$

$y=5$ is not a solution for the equation $10y = 80$ 

Therefore, the equation is not satisfied.

(d) $4l = 20$

If $l = 20$ then $4l=4(20)=80$

$l=20$ is not a solution for the equation $4l = 20$ 

Therefore, the equation is not satisfied.

(e) $4l = 20$

If $l = 20$ then $4l=4(20)=80$

$l=20$ is a solution for the equation $4l = 80$ 

Therefore, the equation is satisfied.

(f) $4l = 20$

If $l = 5$ then $4l=4(5)=20$

$l=5$ is a solution for the equation $4l = 20$ 

Therefore, the equation is satisfied.

(g) $b + 5 = 9$

If $b = 5$ then $b+5=5+5=10$

$b=5$ is not a solution for the equation $b+5 = 9$ 

Therefore, the equation is not satisfied.

(h) $b + 5 = 9$

If $b = 9$ then $b+5=9+5=14$

$b=9$ is not a solution for the equation $b+5 = 9$ 

Therefore, the equation is not satisfied.

(i) $b + 5 = 9$

If $b =4$ then $b+5=4+5=9$

$b=4$ is a solution for the equation $b+5 = 9$ 

Therefore, the equation is satisfied.

(j) $h - 8 = 5$

If $h =13$ then $h-8=13-8=5$

$h=13$ is a solution for the equation $h-8= 5$ 

Therefore, the equation is satisfied.

(k) $h - 8 = 5$

If $h = 8$ then $h-8=8-8=0$

$h=8$ is not a solution for the equation $h-8 = 5$ 

Therefore, the equation is not satisfied.

(l) $h - 8 = 5$

If $h = 0$ then $h-8=0-8=-8$

$h=0$ is not a solution for the equation $h-8 = 5$ 

Therefore, the equation is not satisfied.

(m) $p + 3 = 1$

If $p = 3$ then $p+3=3+3=6$

$p=3$ is not a solution for the equation $p+3 = 6$ 

Therefore, the equation is not satisfied.

(n) $p + 3 = 1$

If $p = 1$ then $p+3=1+3=4$

$p=1$ is not a solution for the equation $p+3 = 1$ 

Therefore, the equation is not satisfied.

(o) $p + 3 = 1$

If $p = 0$ then $p+3=0+3=3$

$p=0$ is not a solution for the equation $p+3 = 1$ 

Therefore, the equation is not satisfied.

(p) $p + 3 = 1$

If $p = -1$ then $p+3=-1+3=2$

$p=-1$ is not a solution for the equation $p+3 = 1$ 

Therefore, the equation is not satisfied.

(q) $p + 3 = 1$

If $p = -2$ then $p+3=-2+3=1$

$p=-2$ is not a solution for the equation $p+3 = 1$ 

Therefore, the equation is satisfied.

raja
Updated on 10-Oct-2022 13:36:48

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