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BitConverter.ToInt32() Method in C#
The BitConverter.ToInt32() method in C# is used to return a 32-bit signed integer converted from four bytes at a specified position in a byte array.
Syntax
The syntax is as follows −
public static int ToInt32 (byte[] val, int begnIndex);
Above, val is the byte array, whereas begnIndex is the beginning position within val.
Example
Let us now see an example −
using System;
public class Demo {
public static void Main(){
byte[] arr = { 10, 20, 30, 40, 50};
Console.WriteLine("Byte Array = {0} ", BitConverter.ToString(arr));
for (int i = 1; i < arr.Length - 3; i = i + 4) {
int res = BitConverter.ToInt32(arr, i);
Console.WriteLine("
Value = "+arr[i]);
Console.WriteLine("Result = "+res);
}
}
}Output
This will produce the following output −
Byte Array = 0A-14-1E-28-32 Value = 20 Result = 841489940
Example
Let us now see another example −
using System;
public class Demo {
public static void Main(){
byte[] arr = { 0, 0, 10, 15, 20, 26, 32, 34, 40};
Console.WriteLine("Byte Array = {0} ", BitConverter.ToString(arr));
for (int i = 1; i < arr.Length - 3; i = i + 4) {
int res = BitConverter.ToInt32(arr, i);
Console.WriteLine("
Value = "+arr[i]);
Console.WriteLine("Result = "+res);
}
}
}Output
This will produce the following output −
Byte Array = 00-00-0A-0F-14-1A-20-22-28 Value = 0 Result = 336529920 Value = 26 Result = 673325082
Updated on: 03-Dec-2019
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