The BitConverter.ToInt32() method in C# is used to return a 32-bit signed integer converted from four bytes at a specified position in a byte array.
The syntax is as follows −
public static int ToInt32 (byte[] val, int begnIndex);
Above, val is the byte array, whereas begnIndex is the beginning position within val.
Let us now see an example −
using System; public class Demo { public static void Main(){ byte[] arr = { 10, 20, 30, 40, 50}; Console.WriteLine("Byte Array = {0} ", BitConverter.ToString(arr)); for (int i = 1; i < arr.Length - 3; i = i + 4) { int res = BitConverter.ToInt32(arr, i); Console.WriteLine("\nValue = "+arr[i]); Console.WriteLine("Result = "+res); } } }
This will produce the following output −
Byte Array = 0A-14-1E-28-32 Value = 20 Result = 841489940
Let us now see another example −
using System; public class Demo { public static void Main(){ byte[] arr = { 0, 0, 10, 15, 20, 26, 32, 34, 40}; Console.WriteLine("Byte Array = {0} ", BitConverter.ToString(arr)); for (int i = 1; i < arr.Length - 3; i = i + 4) { int res = BitConverter.ToInt32(arr, i); Console.WriteLine("\nValue = "+arr[i]); Console.WriteLine("Result = "+res); } } }
This will produce the following output −
Byte Array = 00-00-0A-0F-14-1A-20-22-28 Value = 0 Result = 336529920 Value = 26 Result = 673325082