BitConverter.ToInt16() Method in C#

The BitConverter.ToInt16() method in C# is used to return a 16-bit signed integer converted from two bytes at a specified position in a byte array.

Syntax

The syntax is as follows −

public static short ToInt16 (byte[] val, int begnIndex);

Above, val is the byte array, whereas begnIndex is the beginning position within val.

Example

Let us now see an example −

 Live Demo

using System;
public class Demo {
   public static void Main(){
      byte[] arr = { 0, 0, 7, 10, 18, 20, 25, 26, 32};
      Console.WriteLine("Byte Array = {0} ", BitConverter.ToString(arr));
      for (int i = 1; i < arr.Length - 1; i = i + 2) {
         short res = BitConverter.ToInt16(arr, i);
         Console.WriteLine("
Value = "+arr[i]);
         Console.WriteLine("Result = "+res);
      }
   }
}

Output

This will produce the following output −

Byte Array = 00-00-07-0A-12-14-19-1A-20
Value = 0
Result = 1792
Value = 10
Result = 4618
Value = 20
Result = 6420
Value = 26
Result = 8218

Example

Let us now see another example −

 Live Demo

using System;
public class Demo {
   public static void Main(){
      byte[] arr = { 10, 20, 30};
      Console.WriteLine("Byte Array = {0} ", BitConverter.ToString(arr));
      for (int i = 1; i < arr.Length - 1; i = i + 2) {
         short values = BitConverter.ToInt16(arr, i);
         Console.WriteLine("
Value = "+arr[i]);
         Console.WriteLine("Result = "+values);
      }
   }
}

Output

This will produce the following output −

Byte Array = 0A-14-1E
Value = 20
Result = 7700