BitConverter.Int64BitsToDouble() Method in C#


The BitConverter.Int64BitsToDouble() method in C# is used to reinterpret the specified 64-bit signed integer to a double-precision floating-point number.

Syntax

Following is the syntax −

public static double Int64BitsToDouble (long val);

Above, the parameter value is the number to convert.

Example

Let us now see an example to implement the BitConverter.Int64BitsToDouble() method −

using System;
public class Demo {
   public static void Main(){
      long d = 9846587687;
      Console.Write("Value (64-bit signed integer) = "+d);
      double res = BitConverter.Int64BitsToDouble(d);
      Console.Write("\nValue (double-precision floating point number) = "+res);
   }
}

Output

This will produce the following output −

Value (64-bit signed integer) = 9846587687
Value (double-precision floating point number) = 4.86486070491012E-314

Example

Let us see another example −

using System;
public class Demo {
   public static void Main(){
      long d = 20;
      Console.Write("Value (64-bit signed integer) = "+d);
      double res = BitConverter.Int64BitsToDouble(d);
      Console.Write("\nValue (double-precision floating point number) = "+res);
   }
}

Output

This will produce the following output −

Value (64-bit signed integer) = 20
Value (double-precision floating point number) = 9.88131291682493E-323
raja
Published on 07-Nov-2019 06:30:36
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