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Articles by Nishu Kumari
Page 2 of 9
Alternate Primes till N in C++?
A prime number is a number greater than 1 that is divisible only by 1 and itself. Given a number N, our task is to print all alternate prime numbers up to N. This means we skip every second prime number and only print the 1st position, 3rd position, 5th position, and so on. Let's look at the example scenarios to understand the problem clearly: Scenario 1 Input: N = 15 Output: 2 5 11 Explanation: Prime numbers up to 15 are: 2, 3, 5, 7, 11, 13 Taking alternate primes (1st, 3rd, 5th): 2, 5, 11 Scenario 2 ...
Read MoreAlternate vowel and consonant string in C/C++?
We are given a string with both vowels and consonants. Our task is to rearrange it so that vowels and consonants appear alternately, while keeping their original order within their groups. This rearrangement is only possible if the number of vowels and consonants is equal, or their difference is exactly one. If multiple valid arrangements are possible, we return the one that is lexicographically smaller. Let's understand this with a few example scenarios. Scenario 1 Input: "objective" Output: "bojecitev" Explanation: Vowels = [o, e, i, e], Consonants = [b, j, c, t, v] Consonants are more by 1 -> valid ...
Read MoreAlternate Fibonacci Numbers in C++
The Fibonacci sequence starts from 0 and 1, and each number is the sum of the previous two. In this problem, we are given a number n, and we need to print the first n numbers from the Fibonacci series, but only the numbers at alternate positions (like 0th, 2nd, 4th, and so on). Let's look at some example scenarios to understand it clearly: Scenario 1 Input: n = 7 Output: 0 1 3 8 Explanation: The first 7 Fibonacci numbers are 0 1 1 2 3 5 8. If we pick alternate numbers (index 0, 2, ...
Read MoreAdd One Row to Tree in C++
We are given the root of a binary tree and two integers, val and depth. The root of the binary tree is at depth 1. Our task is to add a new row of nodes with value val at the given depth. If the depth is 1, we have to create a new root node with value val and make the original tree its left child. If the depth is greater than 1, we go to all nodes at depth depth - 1, add new left and right child nodes with value val, and connect the original left and right ...
Read MoreAlternate Lower Upper String Sort in C++
We are given a string that contains both lowercase and uppercase characters, and we have to sort them in an alternate way, meaning one lowercase letter, then one uppercase letter, then again a lowercase letter, and so on, all in sorted order within their cases. Let's understand this with a few example scenarios. Scenario 1 Input: "aFegrAfStRzsV" Output: "AagfRsSeTvz" Explanation: Sorted uppercase letters: A, F, R, S, T, V Sorted lowercase letters: a, e, f, g, r, s, z We place one uppercase letter, then one lowercase letter, starting with an uppercase. We repeat this until all letters ...
Read MoreAdding one to number represented as array of digits in C++?
In this problem, we are given a number in the form of an array, and each digit of the number is stored at one index of the array, and the most significant digit comes first. Our task is to add 1 to this number and return the updated number in the same array format. Let's understand it with some example scenarios. Scenario 1 Input: Input_arr[] = {2, 6, 1} Output: 262 Explanation: The array represents 261. Adding 1 gives 261 + 1 = 262. Scenario 2 Input: input_arr[] = {5, 9, 9, 9} Output: 6000 Explanation: The array ...
Read MoreAlternate Odd and Even Nodes in a Singly Linked List in C++
Given a singly linked list, we need to rearrange its nodes so that even and odd numbers come one after the other alternatively. If the list starts with an even number, the next should be odd, then even, and so on. Similarly, if it begins with an odd number, the next should be even, then odd, and so on. Let's look at some example scenarios to understand the concept better. Scenario 1 Input: 45 -> 21 -> 2 -> 213 -> 3 -> 34 -> 78 -> 12 Output: 45 -> 2 -> 21 -> 34 -> 213 -> 78 ...
Read MoreAdditive Number in C++
We are given a string containing only digits from 0 to 9, and we need to check whether it is an additive number. An additive number is a string that can form an additive sequence, where each number (starting from the third) is the sum of the previous two. For the sequence to be valid, it must have at least three numbers. Let's look at the example scenarios to understand the problem clearly: Scenario 1 Input: "112358" Output: true Explanation: The digits can form the sequence: 1, 1, 2, 3, 5, 8 Here, 1 + 1 = 2 1 ...
Read MoreAdd Bold Tag in String in C++
A string is a sequence of characters, like words, numbers, or sentences, enclosed in double quotes ("). The given task is to add a closed pair of HTML bold tags around a string using C++.Let us understand this with an example: Input: abc Output: abc Add Bold Tag in String in C++ To add bold tags to a string in C++, we use string concatenation. This is the process of joining two or more strings together to form a new string. In C++, this can be done using the '+' operator. To wrap a string with bold ...
Read MoreAdd two numbers using ++ operator in C++.
Adding two numbers is a basic arithmetic operation, where we simply combine their values to get the total. The given task is to add two numbers using the "++" operator in C++. Let's understand this with an example: Scenario 1 // Adding two numbers using '+' operator Input: a = 7, b = 3 Output: 10 Explanation: a + b => 7 + 3 = 10 Scenario 2 // Adding two numbers using '++' operator Input: a = 7, b = 3 Output: 10 Explanation: a + b => 7 + 1 + ...
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