Server Side Programming Articles - Page 1625 of 2646

Suppose we have two strings P and Q of same lengths with only lower case letters, we have to count the minimum number of pre-processing moves on string P are needed to make it equal to string Q after applying below operations −Select any index i and swap characters pi and qi.Select any index i and swap characters pi and pn – i – 1.Select any index i and swap characters qi and qn – i – 1.Note − The value of i in range (0 ≤ i < n)In one move we can change a character in P with any ... Read More

Suppose we have one N X N matrix M, and this is filled with 1, 0, 2, 3, We have to find the minimum numbers of moves required to move from source cell to destination cell. While visiting through blank cells only, we can visit up, down, right and left.Cell with value 1 indicates Source.Cell with value 2 indicates Destination.Cell with value 3 indicates Blank cell.Cell with value 0 indicates Blank Wall.There will be only one source and only one destination cells. There may be more than one path to reach destination from source cell. Now, each move in matrix ... Read More

Suppose we have a given unsorted array A[0..n-1] of size n, we have to find the minimum length subarray A[s..e] so that by sorting this subarray the whole array will be sorted. So, if the array is like [2, 6, 4, 8, 10, 9, 15], then the output will be 5. The subarray will be [6, 4, 8, 10, 9].To solve this, we will follow these steps −res := sort the nums as an arrayans := 0set r as a linked listfor i in range 0 to length of resif nums[i] is not same as res[i], then insert i into ... Read More

Suppose we have two numbers p and q, we have to find the minimum difference between any terms in the shifted infinite tables of p and q, these shifts are r and s, where r, s >= 0.So, if the input is like p = 7 and q = 17, r = 6 and s = 3, then the output will be 0 as, table of 7 = [7, 14, 21, 28, 35, 42, 49, ...] and table of 17 = [17, 34, 51, 68, 85, 102, 119, ...], then shifted table of 7 will be [13, 20, 27, 34, ... Read More

Suppose there is a candy store where N different types of candies are available and the prices of all N different types of candies are given. The store also provides an attractive offer. According to this offer, we can buy a single candy from the store and get maximum of K different types of other candies for free. We have to find the minimum amount of money we have to spend to buy all the N different types of candies. We also have to find maximum amount of money we have to spend to buy all the N different types ... Read More

Suppose we have an array of size n, if the elements in the array, are in range from 0 to k-1. Where k is denoted as a positive integer and k max_val, thenmax_val := A[i]result := ireturn resultExample Let us see the following implementation to get better understanding − Live Demodef get_max_repeating(A, k):    n = len(A)    for i in range(n):       A[A[i]%k] += k    max_val = A[0]    result = 0    for i in range(1, n):       if A[i] > max_val:          max_val = A[i]          result ... Read More

Suppose we have a given number N that in range (1= j and table[i - j] != -1):             table[i] = max(table[i], table[i - j] + 1)    return table def max_summ(table, n):    if (n < max_val):       return table[n]    else:       t = int((n - max_val) / 4)+ 1       return t + table[n - 4 * t] n = 16 table = pre_calc() print(max_summ(table, n))Input16Output4

Suppose there are n bikes and each can cover 100 km when they are fully fueled. We have to find the maximum amount of distance we can go using these n bikes. Here we can assume that all bikes are similar and a bike consumes 1 litre of fuel to cover 1 km distance. So, if n bikes start from same point and run parallel, we can go only 100 km, in this case our target is to cover maximum distance, with minimum fuel. And minimum wastage of fuel means minimum number of bikes used. If the bikes run serially, ... Read More

Suppose we have an array of pairs A; we have to find the maximum cost for selecting at most K pairs. In this case, the cost of an array of pairs type elements is the product of the sum of first elements of the selected pair and the smallest among the second elements of the selected pairs. As an example, if these pairs are selected (4, 8), (10, 3) and (3, 6), then the cost will be (4+10+3)*(3) = 51, for K=3So, if the input is like A = [(15, 5), (65, 25), (35, 20), (20, 5), (35, 20), (15, ... Read More

Suppose we have a string we have to return the longest possible substring that has exactly k number of unique characters, if there are more than one substring of longest possible length, return any of them.So, if the input is like s = "ppqprqtqtqt", k = 3, then the output will be rqtqtqt as that has length 7.To solve this, we will follow these steps −N := 26Define a function is_ok() . This will take count, kval := 0for i in range 0 to N, doif count[i] > 0, thenval := val + 1return true when (k >= val)From the ... Read More