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Programming Articles - Page 950 of 3366
 
			
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To get the length of the Interval, use the interval.length property. At first, import the required libraries −import pandas as pdOpen interval set using the "closed" parameter with value "neither". An open interval (in mathematics denoted by square brackets) does not contains its endpoints, i.e. the open interval [0, 5] is characterized by the conditions 0 < x < 5interval = pd.Interval(5, 20, closed='neither')Display the interval lengthprint("Interval length...", interval.length) ExampleFollowing is the code import pandas as pd # Open interval set using the "closed" parameter with value "neither" # An open interval (in mathematics denoted by square brackets) does ... Read More
 
			
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To get the left bound for the interval, use the interval.left property. At first, import the required libraries −import pandas as pdUse Timestamps as the bounds to create a time interval. Closed interval set using the "closed" parameter with value "left". Get the left bound for the intervalinterval = pd.Interval(pd.Timestamp('2020-01-01 00:00:00'), pd.Timestamp('2021-01-01 00:00:00'), closed='left') Display the intervalprint("Interval...", interval)Get the left boundprint("The left bound for the Interval...", interval.left) ExampleFollowing is the code import pandas as pd # Use Timestamps as the bounds to create a time interval # Closed interval set using the "closed" parameter with value "left" # Get ... Read More
 
			
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To check if an interval set as open is empty, use the interval.is_empty property. At first, import the required libraries −import pandas as pdOpen interval set using the "closed" parameter with value "neither". An open interval (in mathematics denoted by square brackets) does not contains its endpoints, # i.e. the open interval [0, 5] is characterized by the conditions 0 < x < 5interval = pd.Interval(0, 0, closed='neither') Display the intervalprint("Interval...", interval)Check whether interval is empty when it is open i.e. no endpoints. An Interval that does not contain any points is emptyprint("Is Interval empty? ", interval.is_empty) ExampleFollowing is the ... Read More
 
			
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To check if an interval is empty if closed from both sides, use the interval.is_empty property. At first, import the required libraries −import pandas as pdInterval closed from the both sides. Interval set using the "closed" parameter with value "both"interval = pd.Interval(0, 0, closed='both')Display the intervalprint("Interval...", interval) Check whether interval is empty when it is closed from both sides. An Interval that contains a single point is not empty i.e. False is returnedprint("Is Interval empty? ", interval.is_empty)ExampleFollowing is the code import pandas as pd # interval closed from the both sides # Interval set using the "closed" parameter with ... Read More
 
			
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To check if an interval is empty if closed from the left side, use the interval.is_empty property. At first, import the required libraries −import pandas as pdInterval closed from the left. Interval set using the "closed" parameter with value "left"interval = pd.Interval(0, 0, closed='left') Display the intervalprint("Interval...", interval)Check whether interval is emptyprint("Is Interval empty? ", interval.is_empty) ExampleFollowing is the code import pandas as pd # interval closed from the left # Interval set using the "closed" parameter with value "left" interval = pd.Interval(0, 0, closed='left') # display the interval print("Interval...", interval) # display the interval length print("Interval ... Read More
 
			
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To check if an Interval is empty, use the interval.is_empty property. At first, import the required libraries −import pandas as pdCreate an intervalinterval = pd.Interval(0, 0, closed='right') Display the intervalprint("Interval...", interval)Check whether interval is emptyprint("Is Interval empty? ", interval.is_empty) ExampleFollowing is the code import pandas as pd # Create an interval interval = pd.Interval(0, 0, closed='right') # display the interval print("Interval...", interval) # display the interval length print("Interval length...", interval.length) # check whether interval is empty print("Is Interval empty? ", interval.is_empty)OutputThis will produce the following code Interval... (0, 0] Interval length... 0 Is Interval ... Read More
 
			
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Suppose we are given three integer numbers n, x, y, and z. We have to make a sequence from the given integers where the first item of the sequence is (x modulo 231). Other than the first element, other elements in the sequence ai = (a(i-1) * y + z) modulo 231 , where 1 ≤ i ≤ n - 1. We have to find out the number of distinct integers in the sequence we made.So, if the input is like n = 5, x = 1, y = 2, z = 1, then the output will be 5.The unique ... Read More
 
			
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Suppose there is a film festival going on that showcase various movies from various countries. Now, an attendee wants to attend the maximum number of movies that do not overlap with each other and we have to help them to find out how many movies they can attend.There is a structure Movie that has the following members −The beginning time of the movie.The duration of the movie.The ending time of the movie.There is another structure Festival with the following members −The number of movies at the festival.An array of type Movie whose size is similar to the number of movies ... Read More
 
			
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Suppose we are given a list that contains natural numbers. Now from that list, we remove all the numbers that contain two consecutive 1s in its binary representation and generate another list called Z. Now we are given another list 'input_list' that contains some integer values. We have to find out the XOR value of the specified elements from Z whose indexes are specified in input_list.So, if the input is like input_list = [3, 4, 5], then the output will be 9.In indexes 3, 4, and 5 of Z; the values are 4, 5, and 8. So, 4 XOR 5 ... Read More
 
			
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Suppose we are given three integer numbers c, m, and n. We have to generate an infinite sequence, where the first value is 0, the second value is c, and from the third value onwards it is equal to ki = (ki-2 + ki-1) mod m. We have to generate all the values in the series up to item k2n+1. Now from the values of the series; we take two consecutive values in the sequence as the x and y coordinates of a two-dimensional vector and generate n number of vectors. Point to be noted, we use the values in ... Read More