Programming Articles

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Print a String in wave pattern in C++

sudhir sharma
sudhir sharma
Updated on 11-Mar-2026 624 Views

In this problem, we are given a string and an integer n. Our task is to print the given string in a wave pattern of n lines.Let’s take an example to understand the problem, Input: Tutorial n = 3 Output: T             r    U       o       i       s       t                lWave patterns are printed by printing each character of the string one by one in the next line and tab space away from the next element till ...

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Find the common nodes in two singly linked list in C++

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 514 Views

Suppose we have two singly-linked lists. We have to find the total number of common nodes in both the singly linked list. So if two lists are like [15, 16, 10, 9, 7, 17], and [15, 16, 40, 6, 9], there are three common nodes.Traverse both lists up to end of the list using two nested loops, for every node in the list, check if it is matched with any node of the second list or not. If a match is found, then increase the counter, and finally return the count.Example#include using namespace std; class Node {    public:   ...

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Print a pattern without using any loop in C++

sudhir sharma
sudhir sharma
Updated on 11-Mar-2026 767 Views

In this problem, we are given a number n. Our task is to print patterns with decreasing to 0 or negative then increasing back to the number.Let’s take an example to understand the problem,Input: n = 12 Output: 12 7 2 -3 2 7 12To solve this problem, we will use recursion and call the function after each update. The track of update is kept using the flag variable which tells the function to increase or decrease the number by 5.ExampleThe below code gives the implementation of our solution,#include using namespace std; void printNextValue(int m){    if (m > 0){       cout

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Merge Two Binary Trees in C++

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 851 Views

Suppose we have two binary trees and consider that when we put one of them to cover the other, some nodes of the two trees are overlapped while the others are overlapping. We have to merge them into a new binary tree. The merge rule is like that if two nodes are overlapping, then sum node values up as the new value of the merged node. Otherwise, the non-empty node will be used as the node of the new tree.So if the trees are −Then the output will be −To solve this, we will follow these steps −The method is ...

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Find the Diameter or Longest chord of a Circle in C++

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 183 Views

Suppose we have radius r is given. We have to find the diameter or longest chord of the circle. If the radius is 9, and diameter will be 18. This task is extremely simple, we have to find the 2*r, that is the diameter of the circle.Example#include using namespace std; int getDiameter(int r) {    return 2*r; } int main() {    int r = 9;    cout

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Find the K-th minimum element from an array concatenated M times in C++

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 194 Views

Consider we have an array A, and another two integers K and M. We have to find Kth minimum element after concatenating the array to itself M number of times. Suppose the array is like A = [3, 1, 2], K = 4 and M = 3, so after concatenating A, 3 times, it will be [3, 1, 2, 3, 1, 2, 3, 1, 2], the 4th smallest element is 2 here.To solve this problem, we will sort the array A, then return the value, present at index ((K – 1)/M), of the array.Example#include #include using namespace std; int findKSmallestNumber(int ...

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Maximum length of a sub-array with ugly numbers in C++

Narendra Kumar
Narendra Kumar
Updated on 11-Mar-2026 172 Views

Problem statementGiven an array arr[] of N elements (0 ≤ arr[i] ≤ 1000). The task is to find the maximum length of the sub-array that contains only ugly numbers.Ugly numbers are numbers whose only prime factors are 2, 3 or 5.For Example below are the few number from series: 1, 2, 3, 4, 5, 6, 8, 9, 10, 12, 15, …ExampleIf input array is {1, 2, 7, 9, 120, 810, 374} then answer is 3 as −Longest possible sub-array of ugly number sis {9, 120, 810}AlgorithmTake a unordered_set, and insert all the ugly numbers which are less than 1000 in ...

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Two City Scheduling in C++

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 602 Views

Suppose there are 2N persons. A company wants to organize one interview. The cost for flying the i-th person to city A is costs[i][0], and the cost for flying the i-th person to city B is costs[i][1]. We have to find the minimum cost to fly every person to a city, such that N people arrive in every city. So if the given list is [[10, 20], [30, 200], [400, 50], [30, 20]] The output will be 110. So we will send the person P1 to city A with cost 10, Second person to city A with cost 30, third ...

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Maximal Disjoint Intervals in C++

Narendra Kumar
Narendra Kumar
Updated on 11-Mar-2026 399 Views

DescriptionGiven a set of N intervals, the task is to find the maximal set of mutually disjoint intervals. Two intervals [i, j] & [k, l] are said to be disjoint if they do not have any point in commonIf intervals are {{10, 20} {23, 35}, {15, 21}, {37, 41}} then maximum non-overlapping disjoint pairs are −{10, 20} {23, 35} {37, 41}Note that we cannot include {15, 21} as it will overlap with {10, 20}Algorithm1. Sort the intervals, with respect to their end points. 2. Traverse the all intervals, if we get two overlapping intervals, then choose the interval with lower ...

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Play with Chips in C++

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 455 Views

Suppose there are some chips, the i-th chip is at present at position chips[i]. We can perform any of the two following types of operations any many numbers of times as we want (possibly zero) on any chip −Move the i-th chip by 2 units to the left side or to the right side with a cost of 0.Move the i-th chip by 1 unit to the left side or to the right side with a cost of 1.Initially, there can be two or more chips. We have to return the minimum cost needed to move all the chips to ...

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