C++ Articles

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Kth odd number in an array in C++

Hafeezul Kareem
Hafeezul Kareem
Updated on 11-Mar-2026 390 Views

In this tutorial, we are going to write a program that finds the k-th odd number from the given array.Let's see the steps to solve the problem.Initialise the array and k.Iterate over the array.If the current element is odd, then decrement the value of k.If k is 0, then return the current element.Return -1.ExampleLet's see the code.#include using namespace std; int findKthOddNumber(int arr[], int n, int k) {    for (int i = 0; i

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Kth prime number greater than N in C++

Hafeezul Kareem
Hafeezul Kareem
Updated on 11-Mar-2026 350 Views

In this tutorial, we are going to write a program that finds the k-th prime number which is greater than the given number n.Initialise the number n.Find all the prime numbers till 1e6 and store it in a boolean array.Write a loop that iterates from n + 1 to 1e6.If the current number is prime, then decrement k.If k is equal to zero, then return i.Return -1.ExampleLet's see the code.#include using namespace std; const int MAX_SIZE = 1e6; bool prime[MAX_SIZE + 1]; void findAllPrimes() {    memset(prime, true, sizeof(prime));    for (int p = 2; p * p

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Kth smallest element after every insertion in C++

Hafeezul Kareem
Hafeezul Kareem
Updated on 11-Mar-2026 286 Views

In this tutorial, we are going to find the k-th smallest element after every insertion.We are going to use the min-heap to solve the problem. Let's see the steps to complete the program.Initialise the array with random data.Initialise the priority queue.Till k - 1 there won't be any k-th smallest element. So, print any symbol u like.Write a loop that iterates from k + 1 to n.Print the root of the min-heap.If the element is greater than the root of the min-heap, then pop the root and insert the element.ExampleLet's see the code.#include using namespace std; void findKthSmallestElement(int elements[], ...

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kth smallest/largest in a small range unsorted array in C++

Hafeezul Kareem
Hafeezul Kareem
Updated on 11-Mar-2026 164 Views

In this tutorial, we are going to write a program that finds the k-th smallest number in the unsorted array.Let's see the steps to solve the problem.Initialise the array and k.Sort the array using sort method.Return the value from the array with the index k - 1.Let's see the code.Example#include using namespace std; int findKthSmallestNumber(int arr[], int n, int k) {    sort(arr, arr + n);    return arr[k - 1]; } int main() {    int arr[] = { 3, 5, 23, 4, 15, 16, 87, 99 }, k = 5;    cout

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Lagrange’s four square theorem in C++

Hafeezul Kareem
Hafeezul Kareem
Updated on 11-Mar-2026 478 Views

In this tutorial, we are going to learn about largrange's four square theorem.The lagranges's four square theorem states that every natural number can be written as sum of squares of 4 numbers.The following code finds the 4 numbers which satisfies the above condition for the given number n.ExampleLet's see the code.#include using namespace std; void printSquareCombinations(int n) {    for (int i = 0; i * i

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Lagrange’s Interpolation in C++

Hafeezul Kareem
Hafeezul Kareem
Updated on 11-Mar-2026 2K+ Views

In this tutorial, we are going to write a program that finds the result for lagranges's interpolation formula.You don't have write any logic for the program. Just convert the formula into code. Let's see the code.Example#include using namespace std; struct Data {    int x, y; }; double interpolate(Data function[], int xi, int n) {    double result = 0;    for (int i = 0; i < n; i++) {       double term = function[i].y;       for (int j = 0; j < n; j++) {          if (j != i) { ...

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Larger of a^b or b^a in C++

Hafeezul Kareem
Hafeezul Kareem
Updated on 11-Mar-2026 383 Views

In this tutorial, we are going to write a program that finds out the larger among the ab and baIt's a straightforward problem. Let's see the steps to solve it.Initialise the values of a and b.Take the log of both the values.Compute the values of $b\:\log\:a$ and $a\:\log\:b$Compare the both values.If $a\:\log\:b$ is greater than $b\:\log\:a$, then print bais greater.If $b\:\log\:a$ is greater than $a\:\log\:b$, then print abis greater.Else print both are equal.ExampleLet's see the code.#include using namespace std; int main() {    int a = 4, b = 7;    long double x = (long double) a * ...

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Largest Even and Odd N-digit numbers in C++

Hafeezul Kareem
Hafeezul Kareem
Updated on 11-Mar-2026 572 Views

In this tutorial, we are going to write a program that finds the largest even and odd number of n digits number.Let's see the steps to solve the problem.Initialise the number n.The largest odd number is pow(10, n) - 1.The largest even number is odd - 1.ExampleLet's see the code.#include using namespace std; void findEvenAndOddNumbers(int n) {    int odd = pow(10, n) - 1;    int even = odd - 1;    cout

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Largest even digit number not greater than N in C++

Hafeezul Kareem
Hafeezul Kareem
Updated on 11-Mar-2026 227 Views

In this tutorial, we are going to write a program that finds the largest number whose digits are all even and not greater than the given n.Let's see the steps to solve the problem.Initialise the number n.Write a loop from i = n .Check whether the digits of current number are all even or not.If the above condition satisfies, then print the number.Else decrement the i.ExampleLet's see the code.#include using namespace std; int allDigitsEven(int n) {    while (n) {       if ((n % 10) % 2){          return 0;       } ...

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Largest K digit number divisible by X in C++

Hafeezul Kareem
Hafeezul Kareem
Updated on 11-Mar-2026 227 Views

In this tutorial, we are going to write a program that finds the largest k-digit number that is divisible by x.Let's see the steps to solve the problem.Initialise the x and k.Find the value of pow(10, k) - 1 which is largest k-digit number.Now, remove the remainder value from the above value to get the largest k-digit number that is divisible by x.ExampleLet's see the code.#include using namespace std; int answer(int x, int k) {    int max = pow(10, k) - 1;    return max - (max % x); } int main() {    int x = 45, k = 7;    cout

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