C++ Articles

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Path Sum III in C++

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 339 Views

Suppose we have given a binary tree in which each node holds an integer key. We have to find the paths that sum to a given value. The path should start from root to leaf. We have to find the path where the sum is same.If the tree is like [5, 4, 8, 11, null, 13, 4, 7, 2, null, null, 5, 1], and sum is 22, then it will be −The paths are [[5, 4, 11, 2], [5, 8, 4, 5]].To solve this, we will follow these steps −Use the dfs function to solve this problem, the dfs is ...

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Merge Two Binary Trees in C++

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 848 Views

Suppose we have two binary trees and consider that when we put one of them to cover the other, some nodes of the two trees are overlapped while the others are overlapping. We have to merge them into a new binary tree. The merge rule is like that if two nodes are overlapping, then sum node values up as the new value of the merged node. Otherwise, the non-empty node will be used as the node of the new tree.So if the trees are −Then the output will be −To solve this, we will follow these steps −The method is ...

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Shift 2D Grid in C++

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 700 Views

Suppose we have one 2D grid of size m x n. We have another variable k. We have to shift the grid k times. The shift operation will be as followsElement at grid G[i, j] moves to G[i, j + 1]Element at grid G[i, n – 1] moves to G[i + 1, 0]Element at grid G[m - 1, n – 1] moves to G[0, 0]So if the grid is like −123456789The output will be −912345678To solve this, we will follow these steps −The shift operation will take the matrix as inputn = number of rows, m := number of columns, ...

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Convert Binary Number in a Linked List to Integer in C++

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 923 Views

Suppose we have one ‘head’ which is a reference node to a singly-linked list. The value of each node present in the linked list is either 0 or 1. This linked list stores the binary representation of a number. We have to return the decimal value of the number present in the linked list. So if the list is like [1, 0, 1, 1, 0, 1]To solve this, we will follow these steps −x := convert the list elements into an arraythen reverse the list xans := 0, and temp := 1for i in range i := 0, to size ...

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Copy set bits in a range in C++

Ayush Gupta
Ayush Gupta
Updated on 11-Mar-2026 503 Views

In this tutorial, we will be discussing a program to copy set bits of one number to another in the given range.For this we will be provided with two integers. Our task is to see the bits in the first number and set those bits in the second number as well if they are in the given range. Finally returning the digit produced.Example#include using namespace std; //copying set bits from y to x void copySetBits(unsigned &x, unsigned y, unsigned l, unsigned r){    //l and r should be between 1 and 32    if (l < 1 || r ...

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Convex Hull Monotone chain algorithm in C++

Ayush Gupta
Ayush Gupta
Updated on 11-Mar-2026 315 Views

In this tutorial, we will be discussing a program to find the convex hull of a given set of points.Convex hull is the smallest polygon convex figure containing all the given points either on the boundary on inside the figure.Example#include #define llu long long int using namespace std; //structure for the given point struct Point {    llu x, y;    bool operator= t && calc_crossproduct(ans[k - 2],       ans[k - 1], A[i - 1])

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Convex Hull using Divide and Conquer Algorithm in C++

Ayush Gupta
Ayush Gupta
Updated on 11-Mar-2026 1K+ Views

In this tutorial, we will be discussing a program to find the convex hull of a given set of points.Convex hull is the smallest polygon convex figure containing all the given points either on the boundary on inside the figure.In this program, we will use brute force to divide the given points into smaller segments and then finally merging the ones that follow on to construct the convex hull.Example#include using namespace std; //storing the center point of polygon pair mid; //calculating the quadrant of //a particular point int quad(pair p){    if (p.first >= 0 && p.second >= 0)   ...

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Coordinates of rectangle with given points lie inside in C++

Ayush Gupta
Ayush Gupta
Updated on 11-Mar-2026 278 Views

In this tutorial, we will be discussing a program to find the coordinates of rectanglewith given points lying inside.For this we will be provided with some coordinate points. Our task is to find the smallest rectangle such that all the points lie inside it and it should have its sides parallel to the coordinate axis.Example#include using namespace std; //calculating the coordinates of smallest rectangle void print_rectangle(int X[], int Y[], int n){    //finding minimum and maximum points    int Xmax = *max_element(X, X + n);    int Xmin = *min_element(X, X + n);    int Ymax = *max_element(Y, Y ...

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Converting seconds into days, hours, minutes and seconds in C++

Ayush Gupta
Ayush Gupta
Updated on 11-Mar-2026 1K+ Views

In this tutorial, we will be discussing a program to convert seconds into days, hours, minutes and seconds.For this we will be provided with a random number of seconds. Our task is to convert it into proper number of days, hours, minutes and seconds respectively.Example#include using namespace std; //converting into proper format void convert_decimal(int n) {    int day = n / (24 * 3600);    n = n % (24 * 3600);    int hour = n / 3600;    n %= 3600;    int minutes = n / 60 ;    n %= 60;    int seconds = n;    cout

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Converting Roman Numerals to Decimal lying between 1 to 3999 in C++

Ayush Gupta
Ayush Gupta
Updated on 11-Mar-2026 434 Views

In this tutorial, we will be discussing a program to converting roman numerals to decimal lying between 1 to 3999.For this we will be provided with a random roman numeral. Our task is to convert the given roman numeral into its decimal equivalent.Example#include using namespace std; //calculating the decimal value int value(char r){    if (r == 'I')    return 1;    if (r == 'V')    return 5;    if (r == 'X')    return 10;    if (r == 'L')    return 50;    if (r == 'C')    return 100;    if (r == 'D')    return ...

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