C++ Articles

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Delete alternate nodes of a Linked List in C++

Hafeezul Kareem
Hafeezul Kareem
Updated on 11-Mar-2026 1K+ Views

In this tutorial, we are going to learn how to delete all prime nodes from a singly linked list.Let's see the steps to solve the problem.Write struct with data and next pointer.Write a function to insert the node into the singly linked list.Initialize the singly linked list with dummy data.Iterate over the singly linked list.Delete alternate node by maintaining the previous node.Write a function to delete the node. Consider the following three cases while deleting the node.If the node is head node, then move the head to next node.If the node is middle node, then link the next node to ...

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Count trailing zeros in factorial of a number in C++

Sunidhi Bansal
Sunidhi Bansal
Updated on 11-Mar-2026 2K+ Views

Given an integer number as input. The goal is to find the number of trailing zeroes in the factorial calculated for that number. A factorial of a number N is a product of all numbers in the range [1, N].We know that we get a trailing zero only if the number is multiple of 10 or has a factor pair (2, 5). In all factorials of any number greater than 5, we have a number of 2s more than 5s in prime factorization of that number. Dividing a number by powers of 5 will give us the count of 5s ...

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Count ways to express 'n' as sum of odd integers in C++

Sunidhi Bansal
Sunidhi Bansal
Updated on 11-Mar-2026 427 Views

Given an integer n as input. The goal is to find the number of ways in which we can represent ‘n’ as the sum of odd integers. For example, if n is 3 it can be represented as sum ( 1+1+1 ) and (3) so total 2 ways.For ExampleInputn=6OutputCount of ways to express ‘n’ as sum of odd integers are: 8ExplanationThe ways in which we can express ‘n’ as sum of odd integers − 1. 1+1+1+1+1+1 2. 3+1+1+1 3. 1+3+1+1 4. 1+1+3+1 5. 1+1+1+3 6. 3+3 7. 1+5 8. 5+1Inputn=9OutputCount of ways to express ‘n’ as sum of odd integers ...

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Count ways to express a number as sum of powers in C++

Sunidhi Bansal
Sunidhi Bansal
Updated on 11-Mar-2026 1K+ Views

Given two numbers num and power as input. The goal is to find the ways in which num can be represented as a sum of unique natural numbers raised to the given power. If num is 10 and power is 2 then we can represent 10 as 12+32. So total 1 way.For ExampleInputnum=30OutputCount of ways to express a number as sum of powers are: 2ExplanationThe ways in which we can express 30 as sum of powers: 12 + 22 + 52 and 12 + 22 + 32 + 42Inputnum=35OutputCount of ways to express a number as sum of powers are: ...

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Count the number of ways to traverse a Matrix in C++

Sunidhi Bansal
Sunidhi Bansal
Updated on 11-Mar-2026 386 Views

Given a 2D matrix with dimensions row X col. The goal is to count the number of ways one can traverse the matrix from cell 0, 0 to cell row, col using only right and down moves, i.e. first move can be 0, 0 to 0, 1 (down) or 1, 0 (right) and not 1, 1(diagonal).For ExampleInputcol = 2; row = 4OutputCount of number of ways to traverse a Matrix are: 4ExplanationThe ways in which we can reach from cell 0, 0 to 2, 4 is shown −Inputcol = 4; row = 3OutputCount of number of ways to traverse a ...

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Count number of trailing zeros in Binary representation of a number using Bitset in C++

Sunidhi Bansal
Sunidhi Bansal
Updated on 11-Mar-2026 4K+ Views

Given an integer num as input. The goal is to find the number of trailing zeroes in the binary representation of num using bitset.A bitset stores the bits 0s and 1s in it. It is an array of bits.For ExampleInputnum = 10OutputCount of number of trailing zeros in Binary representation of a number using Bitset are: 1ExplanationThe number 10 in binary is represented as 1010 so trailing zeroes in it is 1.Inputnum = 64OutputCount of number of trailing zeros in Binary representation of a number using Bitset are: 6ExplanationThe number 64 in binary is represented as 10000000 so trailing zeroes ...

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Count of all N digit numbers such that num + Rev(num) = 10^N - 1 in C++

Sunidhi Bansal
Sunidhi Bansal
Updated on 11-Mar-2026 205 Views

Given a number N as input. The goal is to find the count of all N digit numbers that have sum Count of all N digit numbers such that num + Rev(num) = 10N − 1num+rev(num)=10N−1For ExampleInputN=4OutputCount of all N digit numbers such that num + Rev(num) = 10N − 1 are − 90ExplanationThe numbers would be − 1. 1188 + 8811 = 9999 2. 2277 + 7722 = 9999 3. 1278 + 8721 = 9999 ……...total 90 numbersInputN=5OutputCount of all N digit numbers such that num + Rev(num) = 10N − 1 are − 0ExplanationAs N is odd, ...

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Count of Binary Digit numbers smaller than N in C++

Sunidhi Bansal
Sunidhi Bansal
Updated on 11-Mar-2026 361 Views

Given an integer N as input. The goal is to find the count of integers that are less than N and represented in Binary form. For example if input N is 12 then numbers less than 12 are 1, 10, 11 that are binary and contain 0s and 1s as digits. The answer would be 3.For ExampleInputN=100OutputCount of Binary Digit numbers smaller than N are − 4ExplanationThe Binary numbers less than 100 are − 1, 10, 11, 100InputN=120OutputCount of Binary Digit numbers smaller than N are: 7ExplanationThe Binary numbers less than 100 are : 1, 10, 11, 100, 101, 110, ...

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Count the number of holes in an integer in C++

Sunidhi Bansal
Sunidhi Bansal
Updated on 11-Mar-2026 598 Views

Given an array of holes[10] containing a number of holes in numbers 0 to 9. The goal is to find the number of holes in an integer number given as input. Given − holes[] = { 2, 1, 1, 0, 0, 1, 1, 1, 0 }For ExampleInputnumber = 239143OutputCount the number of holes in an integer are: 3ExplanationWe will count holes given in holes[] 239143 ( 1+0+0+2+0+0 )Inputnumber = 12345OutputCount the number of holes in an integer are: 3ExplanationWe will count holes given in holes[] 12345 ( 1+1+0+0+1)Approach used in the below program is as follows −Simply take each leftmost ...

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Count subsets that satisfy the given condition in C++

Sunidhi Bansal
Sunidhi Bansal
Updated on 11-Mar-2026 487 Views

Given an array of numbers and an integer x as input. The goal is to find all the subsets of arr[] such that individual elements of that set as well as the sum of them fully divisible by x.For ExampleInputarr[] = {1, 2, 3, 4, 5, 6} x=3OutputCount of subsets that satisfy the given condition :3ExplanationThe subsets will be: [3], [6], [3, 6]Inputarr[] = {1, 2, 3, 4, 5, 6} x=4OutputCount of subsets that satisfy the given condition :1ExplanationThe subsets will be: [4]Approach used in the below program is as follows −In this approach we will count the elements of ...

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