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C++ Articles
Page 35 of 597
Different possible marks for n questions and negative marking in C++ Program
In this tutorial, we are going to write a program that finds different possible marks for the given n questions with positive and negative marking.Let's say we have 10 questions and each carries 2 marks for correct answers and -1 marks for a negative answer. Our aim is to find all the possible ways in which a student can score in the exam.Let's see the steps to solve the problem.Initialize the number of questions, positive marks for the correct answer and negative marks for the wrong answer.Initialize a set to store the possible marks.Write two inner loops from 0 to ...
Read MoreDigital Root (repeated digital sum) of the given large integer in C++ Program
In this tutorial, we are going to learn how to find the digital root of a given number.The digital root is the sum of a number of digits (until the sum of the digits becomes a single digit).We are given an integer in string format. And we have to find the sum of the digits repeatedly until the sum becomes a single digit.Let's see the steps to solve the problem.Initialize an integer in the string format.Iterate through the number and add each digit to the sum variable.If the sum is 0, then print 0.Else if the sum is divisible by ...
Read MoreDigits of element wise sum of two arrays into a new array in C++ Program
In this tutorial, we are going to write a program that finds the sun of two array elements and store them into a separate array.We have given two arrays and we need to add the corresponding index elements from the two arrays. If the sum is not single digits, then extract the digits from the number and store them in the new array.Let's see an example.Inputarr_one = {1, 2, 32, 4, 5} arr_two = {1, 52, 3}Output2 5 4 3 5 4 5Let's see the steps to solve the problem.Initialize two arrays with dummy data.We are using the vector to ...
Read MoreDivide a number into two parts in C++ Program
In this tutorial, we are going to write a program that divides the given number into two partsIt's a straightforward problem to solve. We can get a number by diving the given number. And we can get the second number by subtracting the result from the total.If the given number is n, then the two numbers area = n / 2 b = n - aExampleLet's see the code.#include using namespace std; void divideTheNumber(int n) { int a = n / 2; int b = n - a; cout
Read MoreDivide a string in N equal parts in C++ Program
In this tutorial, we are going to write a program that divides the given string into N equal parts.If we can't divide the string into N equal parts, then print the same thing. Let's see the steps to solve the problem.Initialize the string and N.Find the length of the string using the size method.Check whether the string can be divided into N parts or not.If string can't divide into N equal parts, then print a message.Else iterate through the string and print each part.ExampleLet's see the code.#include using namespace std; void divideTheString(string str, int n) { int str_length ...
Read MoreDivide every element of one array by other array elements in C++ Program
In this tutorial, we are going to write a program that divides one array of elements by another array of elements.Here, we are following a simple method to complete the problem. Let's see the steps to solve the problem.Initialize the two arrays.Iterate through the second array and find the product of the elements.Iterate through the first array and divide each element with a product of the second array elements.ExampleLet's see the code.#include using namespace std; void divideArrOneWithTwo(int arr_one[], int arr_two[], int n, int m) { int arr_two_elements_product = 1; for (int i = 0; i < m; ...
Read MoreDivide large number represented as string in C++ Program
In this tutorial, we are going to learn how to divide a large number that is represented as a string.We have given a large number in string format and a divisor. Our program should find a reminder.First, we will find a part of the given number that is greater than the dividend. And then we will add the remaining digits one by one to the divisor.Let's see the steps to solve the problem.Initialize the large number along with a divisor.Iterate over the given number until we extract the part that is greater than the divisor.Now, iterate from where we left ...
Read MoreDivisibility by 12 for a large number in C++ Program
In this tutorial, we are going to write a program that checks whether the given large number in string format is divisible by 12 or not.We are going to use a little bit of math to solve this problem. If the number is divisible by 3 and 4, then the number will divisible by 12.A number is divisible by 3 if the sum of its digits is divisible by 3.A number is divisible by 4 if the last two digits of the number are divisible by 4.We are going to utilize the above statements and complete the program.ExampleLet's see the ...
Read MoreDivisible by 37 for large numbers in C++ Program
In this tutorial, we are going to write a program that checks whether the given large number is divisible by 37 or not.We are going to use a little bit of math here. Let's see the steps to solve the problem.Initialize the number.If the length of the given number is not divisible by 3, then add zeroes at the beginning of the number to make length is divisible by 3.Divide the number into 3 digits groups and add them.If the resultant sum is divisible by 37, then the given number is divisible by 37.If the resultant sum is 4 digits ...
Read MoreDivision without using '/' operator in C++ Program
In this tutorial, we are going to learn how to divide a number without using the division (/) operator.We have given two numbers, the program should return the quotient of the division operation.We are going to use the subtraction (-) operator for the division.Let's see the steps to solve the problem.Initialize the dividend and divisor.If the number is zero, then return 0.Store whether the result will be negative or not by checking the signs of dividend and divisor.Initialize a count to 0.Write a loop that runs until the number one is greater than or equals to the number two.Subtract the ...
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