Articles on Trending Technologies

Technical articles with clear explanations and examples

Find the product of first k nodes of the given Linked List in C++

Arnab Chakraborty
Arnab Chakraborty
Updated on 04-Nov-2019 165 Views

Consider we have few elements in a linked list. We have to find the multiplication result of first k number of elements. The value of k is also given. So if the list is like [5, 7, 3, 5, 6, 9], and k = 3, then result will be 5 * 7 * 3 = 105.The processes is straight forward. We simply read the current element starting from left side, then multiply it with the prod. (initially prod is 1), when k number of elements are traversed, then stop.Example#include #include using namespace std;    class Node{       public: ...

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Find the perimeter of a cylinder in C++

Arnab Chakraborty
Arnab Chakraborty
Updated on 04-Nov-2019 234 Views

Suppose we have the diameter and the height of the cylinder, we have to find the perimeter of the cylinder. As the perimeter is the outline of two dimensional object, then we cannot find the perimeter of one three dimensional object directly. We can make a cross section of the cylinder, and convert it as rectangle, then find the perimeter. The two sides of the rectangular cross section are the diameter, and the height. So perimeter is −p=(2*d)+(2*h)Example#include using namespace std; int getCylinderPerimeter(int d, int h) {    return (2*d) + (2*h); } int main() {    int diameter = ...

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Find the Number which contain the digit d in C++

Arnab Chakraborty
Arnab Chakraborty
Updated on 04-Nov-2019 221 Views

Consider we have a digit d, and the upper limit n. we have to find all numbers that contains d in range 0 to n. So if n = 20, and digit is 3, then the numbers will be [3, 13].To solve this problem, we will take every number as string, then if the digit is present in the string, the number will be printed, otherwise ignored.Example#include using namespace std; int getAllNumWithDigit(int n, int d) {    string str = "";    str += to_string(d);    char ch = str[0];    string p = "";    p += ch;    for (int i = 0; i

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Find the Next perfect square greater than a given number in C++

Arnab Chakraborty
Arnab Chakraborty
Updated on 04-Nov-2019 584 Views

Suppose we have a number n. our task is to find next perfect square number of n. So if the number n = 1000, then the next perfect square number is 1024 = 322.To solve this, we have get the square root of the given number n, then take the floor of it, after that display the square of the (floor value + 1)Example#include #include using namespace std; int justGreaterPerfectSq(int n) {    int sq_root = sqrt(n);    return (sq_root + 1)*(sq_root + 1);    } int main() {    int n = 1000;    cout

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Find the length of each string element in the Numpy array in C++

Arnab Chakraborty
Arnab Chakraborty
Updated on 04-Nov-2019 204 Views

Here we will see how to get the length of each string element in the Numpy Array. Numpy is a library for Numeric Python, and it has very powerful array class. Using this we can store data in an array like structure. To get the length we can follow two different approach, these are like below −Exampleimport numpy as np str_arr = np.array(['Hello', 'Computer', 'Mobile', 'Language', 'Programming', 'Python']) print('The array is like: ', str_arr) len_check = np.vectorize(len) len_arr = len_check(str_arr) print('Respective lengts: ', len_arr)OutputThe array is like: ['Hello' 'Computer' 'Mobile' 'Language' 'Programming' 'Python'] Respective lengts: [ 5 8 6 8 ...

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Find sum of factorials in an array in C++

Arnab Chakraborty
Arnab Chakraborty
Updated on 04-Nov-2019 320 Views

Consider we have an array A, which is sorted. It has all elements appears twice, but one element is present for only one time. We have to find that element. If the array is [1, 1, 3, 3, 4, 4, 5, 6, 6, 7, 7, 9, 9], so the single element is 5.We will use the binary search approach to solve this. All elements before the single element has their first occurrence at index 0, 2, 4, … and first occurrence at index 1, 3, 5, … but after the single element, all occurrences of the first number will be ...

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Find largest word in dictionary by deleting some characters of given string in C++

Samual Sam
Samual Sam
Updated on 01-Nov-2019 285 Views

Consider we have a dictionary, and a string s. Find the longest string in the dictionary, that can be formed by deleting some characters of the string s. Suppose the s is “apbreoigroakml”, The dictionary has {“prog”, “ram”, “program”}, then the result will be “program”.To solve this, we will traverse all dictionary words, and for each word, we will check whether the subsequence of the given string and is longest of all such words. Finally return longest word with given string as subsequence.Example#include #include using namespace std; bool isSubSequence(string s1, string s2) {    int m = s1.length(), n = ...

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Find N digits number which is divisible by D in C++

Arnab Chakraborty
Arnab Chakraborty
Updated on 01-Nov-2019 219 Views

Suppose we have two numbers N and D. We have to find N digit number, that is divisible by D. If N is 3, and D is 5, then the number can be 500. This can be solved easily. If D is 10 and N is 1, then it will be impossible. We can put D, and suppose the D has m number of digits, then attach N – m number of 0s to make it N digit number and divisible by D.Example#include using namespace std; string nDigitDivByD(int n, int d) {    string ans = "";    if (d ...

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Find most significant set bit of a number in C++

Arnab Chakraborty
Arnab Chakraborty
Updated on 01-Nov-2019 2K+ Views

Here we will see if a number is given, then how to find the value of Most Significant Bit value, that is set. The value is power of 2. So if the number is 10, MSB value will be 8.We have to find the position of MSB, then find the value of the number with a set-bit at kth position.Example#include #include using namespace std; int msbBitValue(int n) {    int k = (int)(log2(n));    return (int)(pow(2, k)); } int main() {    int n = 150;    cout

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Find middle of singly linked list Recursively in C++

Arnab Chakraborty
Arnab Chakraborty
Updated on 01-Nov-2019 590 Views

Consider we have a list of numbers; our task is to find the middle of the linked list using recursion. So if the list elements are [12, 14, 18, 36, 96, 25, 62], then the middle element is 36.To solve this problem, we will count total number of nodes in the list in recursive manner and do half of this. Then rolling back through recursion decrement n by 1 in each call, return element where n is zero.Example#include #include using namespace std; class Node{    public:       int data;       Node *next; }; Node* getNode(int data){ ...

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