Splitting number to contain continuous odd or even number using JavaScript

Problem

We need to write a JavaScript function that takes a positive number and splits it into continuous segments of odd or even digits. The function should create a new segment whenever it encounters a digit with different parity (odd becomes even or even becomes odd).

Example

For the number 124579:

• 1 (odd) - starts first segment
• 2, 4 (even) - starts second segment
• 5, 7, 9 (odd) - starts third segment

Solution

Following is the code:

const num = 124579;
const splitDifferent = (num = 1) => {
    const str = String(num);
    const res = [];
    let temp = '';
    for(let i = 0; i < str.length; i++){
        const el = str[i];
        if(!temp || +temp[temp.length - 1] % 2 === +el % 2){
            temp += el;
        }else{
            res.push(+temp);
            temp = el;
        };
    };
    if(temp){
        res.push(+temp);
        temp = '';
    };
    return res;
};
console.log(splitDifferent(num));

Output

[ 1, 24, 579 ]

How It Works

The algorithm converts the number to a string and iterates through each digit:

1. Check if current digit has same parity as the last digit in temp
2. If same parity, append to current segment (temp)
3. If different parity, push current segment to result and start new segment
4. Convert string segments back to numbers in the final array

Additional Examples

// Example with alternating digits
console.log(splitDifferent(13579));  // All odd digits

// Example with all even digits  
console.log(splitDifferent(2468));   // All even digits

// Example with alternating pattern
console.log(splitDifferent(135246)); // Mixed pattern

[ 13579 ]
[ 2468 ]
[ 135, 246 ]

Conclusion

This function efficiently splits numbers into continuous segments based on digit parity. It uses string manipulation and modulo operations to group consecutive odd or even digits together.