Sorting field value (FirstName) for MongoDB?

To sort field values in MongoDB, use the sort() method with field name and sort direction. Use 1 for ascending order and -1 for descending order.

Syntax

db.collection.find().sort({ "fieldName": 1 });  // Ascending
db.collection.find().sort({ "fieldName": -1 }); // Descending

Sample Data

db.demo365.insertMany([
    { "FirstName": "Chris" },
    { "FirstName": "Adam" },
    { "FirstName": "John" },
    { "FirstName": "Bob" }
]);

{
    "acknowledged": true,
    "insertedIds": [
        ObjectId("5e57d5b6d0ada61456dc936f"),
        ObjectId("5e57d5bad0ada61456dc9370"),
        ObjectId("5e57d5bed0ada61456dc9371"),
        ObjectId("5e57d5c0d0ada61456dc9372")
    ]
}

Display all documents from the collection ?

db.demo365.find();

{ "_id": ObjectId("5e57d5b6d0ada61456dc936f"), "FirstName": "Chris" }
{ "_id": ObjectId("5e57d5bad0ada61456dc9370"), "FirstName": "Adam" }
{ "_id": ObjectId("5e57d5bed0ada61456dc9371"), "FirstName": "John" }
{ "_id": ObjectId("5e57d5c0d0ada61456dc9372"), "FirstName": "Bob" }

Example: Sort FirstName in Ascending Order

db.demo365.find().sort({ "FirstName": 1 });

{ "_id": ObjectId("5e57d5bad0ada61456dc9370"), "FirstName": "Adam" }
{ "_id": ObjectId("5e57d5c0d0ada61456dc9372"), "FirstName": "Bob" }
{ "_id": ObjectId("5e57d5b6d0ada61456dc936f"), "FirstName": "Chris" }
{ "_id": ObjectId("5e57d5bed0ada61456dc9371"), "FirstName": "John" }

Example: Sort FirstName in Descending Order

db.demo365.find().sort({ "FirstName": -1 });

{ "_id": ObjectId("5e57d5bed0ada61456dc9371"), "FirstName": "John" }
{ "_id": ObjectId("5e57d5b6d0ada61456dc936f"), "FirstName": "Chris" }
{ "_id": ObjectId("5e57d5c0d0ada61456dc9372"), "FirstName": "Bob" }
{ "_id": ObjectId("5e57d5bad0ada61456dc9370"), "FirstName": "Adam" }

Conclusion

The sort() method arranges documents by specified field values. Use 1 for alphabetical ascending order and -1 for descending order to organize your query results effectively.