Maximum size square submatrix with all 1s

When a binary matrix is given, our task is to find a square matrix whose all elements are 1.

For this problem, we will make an auxiliary size matrix, whose order is the same as the given matrix. This size matrix will help to represent, in each entry Size[i, j], is the size of a square matrix with all 1s. From that size matrix, we will get the maximum number to get the size of the biggest square matrix.

Input and Output

Input:
The binary matrix.
0 1 1 0 1
1 1 0 1 0
0 1 1 1 0
1 1 1 1 1
0 0 0 0 0

Output:
The largest submatrix with all 1’s.

Algorithm

subMatWithOne(given matrix)

Input − The main matrix.

Output − Display the square matrix with all 1, which one is the largest.

Begin
   define subMat whose order is same as given matrix
   copy first row and first column of given matrix to subMat

   for all row i (1 to n), do
      for all column j (1 to n), do
         if matrix[i, j] = 1, then
            subMat[i, j] := 1 + minimum of subMat[i, j-1]
            and subMat[i-1, j-1]
         else
            subMat[i, j] := 0
      done
   done

   maxSize := subMat[0, 0], iMax := 0 and jMax := 0
   for all row i and column j, do
      if maxSize 
Example
#include
#define ROW 6
#define COL 5
using namespace std;

int matrix[ROW][COL] =  {
   {0, 1, 1, 0, 1},
   {1, 1, 0, 1, 0},
   {0, 1, 1, 1, 0},
   {1, 1, 1, 1, 0},
   {1, 1, 1, 1, 1},
   {0, 0, 0, 0, 0}
};

int min(int a, int b, int c) {
   return ((a iMax - maxSize; i--) {    //print the submatrix using max size
      for(int j = jMax; j > jMax - maxSize; j--) {
         cout 
Output
Subsquare matrix:
1 1 1
1 1 1
1 1 1