Golang Program to find the odd-occurring elements in a given array

Examples

For example, arr = [1, 4, 5, 1, 4, 5, 1] => Odd-occurring element in the array is: 1

Approach to solve this problem

Step 1 − Define method that accepts an array.

Step 2 − Declare a xor variable, i.e., xor := 0.

Step 3 − Iterate input array and perform xor operation with each element of the array.

Step 4 − At the end, return xor.

Example

 Live Demo

package main
import (
   "fmt"
)
func FindOddOccurringElement(arr []int) int{
   xor := 0
   for i := 0; i < len(arr); i++ {
      xor = xor ^ arr[i]
   }
   return xor
}
func main(){
   arr := []int{1, 4, 5, 1, 4, 5, 1}
   fmt.Printf("Input array is: %d\n", arr)
   fmt.Printf("Odd occurring element in given array is: %d\n", FindOddOccurringElement(arr))
}

Output

Input array is: [1 4 5 1 4 5 1]
Odd occurring element in given array is: 1