Getting equal or greater than number from the list of numbers in JavaScript

We are required to write a JavaScript function that takes in an array of numbers as the first argument and a single number as the second argument. The function should return an array of all the elements from the input array that are greater than or equal to the number taken as the second argument.

Example

Following is the code ?

const arr = [56, 34, 2, 7, 76, 4, 45, 3, 3, 34, 23, 2, 56, 5];
const threshold = 40;
const findGreater = (arr, num) => {
    const res = [];
    for(let i = 0; i < arr.length; i++){
        if(arr[i] < num){
            continue;
        };
        res.push(arr[i]);
    };
    return res;
};
console.log(findGreater(arr, threshold));

Output

This will produce the following output in console ?

[ 56, 76, 45, 56 ]

Using filter() Method

A more concise approach uses the filter() method to achieve the same result:

const arr = [56, 34, 2, 7, 76, 4, 45, 3, 3, 34, 23, 2, 56, 5];
const threshold = 40;

const findGreaterWithFilter = (arr, num) => {
    return arr.filter(element => element >= num);
};

console.log(findGreaterWithFilter(arr, threshold));

[ 56, 76, 45, 56 ]

Comparison

Handling Edge Cases

Here's a more robust version that handles edge cases like empty arrays and invalid inputs:

const findGreaterSafe = (arr, num) => {
    if (!Array.isArray(arr) || typeof num !== 'number') {
        return [];
    }
    return arr.filter(element => typeof element === 'number' && element >= num);
};

// Test with edge cases
console.log(findGreaterSafe([], 10));           // Empty array
console.log(findGreaterSafe([1, 2, 'a', 4], 2)); // Mixed types
console.log(findGreaterSafe([5, 10, 15], 8));   // Normal case

[]
[ 4 ]
[ 10, 15 ]

Conclusion

Both the for loop and filter() methods effectively find elements greater than or equal to a threshold. The filter() method offers cleaner, more readable code, while the for loop provides slightly better performance for large arrays.