Get all the records with two different values in another column with MySQL

For this, you can use GROUP BY HAVING clause.

Let us first create a table −

mysql> create table DemoTable751 ( 
   StudentName varchar(100),
   SubjectName varchar(100)
);
Query OK, 0 rows affected (0.66 sec)

Insert some records in the table using insert command −

mysql> insert into DemoTable751 values('John','MySQL');
Query OK, 1 row affected (0.14 sec)
mysql> insert into DemoTable751 values('John','MongoDB');
Query OK, 1 row affected (0.14 sec)
mysql> insert into DemoTable751 values('Sam','MySQL');
Query OK, 1 row affected (0.17 sec)
mysql> insert into DemoTable751 values('Carol','Java');
Query OK, 1 row affected (0.21 sec)
mysql> insert into DemoTable751 values('David','MySQL');
Query OK, 1 row affected (0.16 sec)
mysql> insert into DemoTable751 values('Carol','MongoDB');
Query OK, 1 row affected (0.17 sec)

Display all records from the table using select statement −

mysql> select *from DemoTable751;

This will produce the following output -

+-------------+-------------+
| StudentName | SubjectName |
+-------------+-------------+
| John        | MySQL       |
| John        | MongoDB     |
| Sam         | MySQL       |
| Carol       | Java        |
| David       | MySQL       |
| Carol       | MongoDB     |
+-------------+-------------+
6 rows in set (0.00 sec)

Following is the query to get all the records with two different values in MySQL −

mysql> select StudentName from DemoTable751
   group by StudentName
   having count(SubjectName) > 1;

This will produce the following output -

+-------------+
| StudentName |
+-------------+
| John        |
| Carol       |
+-------------+
2 rows in set (0.00 sec)