C Program to print numbers from 1 to N without using semicolon

Printing numbers from 1 to N is an easy task that can be achieved using loops, but to print numbers from one to N without using a semicolon is a tricky question. We will discuss two different methods to solve this question using iteration and recursion approaches.

In this article, our task is to print numbers from 1 to 'n' and we don't have to use a semicolon. The approaches are listed below:

• Using Iteration
• Using Recursion

Using Iteration

This approach uses the iterative approach, where we have used the while loop to print the numbers from 1 to N. The num <=N checks if the number is within the range, we print the numbers using a printf statement and increase the counter of num. We use the logical AND (&&) operator to verify all three conditions are true inside the while loop.

Example

Here is an example of printing numbers from 1 to 20 using an iterative approach. You can change the value of N:

#include<stdio.h>
#define N 20
int main(int num, char *argv[]) {
   while (num <=N && printf("%d ", num) && num++) {
      //The while body is empty.
   }
}

The output of the above code is given below:

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20

Using Recursion

You can use the recursion for printing the numbers from 1 to N without using a semicolon. The if statement along with the logical AND operator checks if the value of N is valid and prints the N. We have recursively called the main() function to print the next number.

Example

In this example, we have printed numbers from 1 to 25 using a recursive approach:

#include<stdio.h>
#define N 25
int main(int val) {
   if (val <=N && printf("%d ", val) && main(val + 1)) {
      //Body is empty
   }
}

The output of the above code is given below:

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25