C Program for Print individual digits as words without using if or switch.

Print the given numeric value as words. It’s easy to do with switch using cases from 0-9 but challenge is without using them.

Input  − N=900
Output − NINE ZERO ZERO

It is possible by creating array of pointers that contains 0-9 in words.

Algorithm

START
Step 1 -> declare int variables num, i and array of pointer char *alpha with values {"ZERO", "ONE", "TWO", "THREE", "FOUR", "FIVE", "SIX", "SEVEN", "EIGHT", "NINE"}
Step 2 -> declare char array str[20]
Step 3 -> call function itoa with parameters num,str,10
Step 4 -> Loop For i=0 and str[i]!=’\o’ and i++
   Print alpha[str[i] - '0']
Step 5 -> End Loop
STOP

Example

#include<stdio.h>
#include<stdlib.h>
int main() {
   int num, i;
   num=900; //lets take numeric value
   char *alpha[11] = {"ZERO", "ONE", "TWO", "THREE", "FOUR", "FIVE", "SIX", "SEVEN", "EIGHT", "NINE"};
   char str[20];
   itoa(num, str, 10); //this function will convert integer to alphabet
   for(i=0; str[i] != '\0'; i++)
      printf("%s ", alpha[str[i] - '0']);
   return 0;
}

Output

If we run above program then it will generate following output

Enter an integer
900
NINE ZERO ZERO