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Area of circle inscribed within rhombus in C Program?
In C, we can calculate the area of a circle inscribed within a rhombus using the diagonals of the rhombus. When a circle is inscribed in a rhombus with diagonals 'a' and 'b', the circle touches all four sides of the rhombus.
Syntax
float circleArea = (M_PI * (a * b * a * b)) / (4 * (a * a + b * b));
Where 'a' and 'b' are the diagonals of the rhombus. The formula is derived from the fact that the radius of the inscribed circle equals (a * b) / (2 * sqrt(a² + b²)).
Mathematical Derivation
The diagonals of a rhombus create four equal right-angled triangles. Each side of the rhombus is the hypotenuse of these triangles −
- Side length = ?((a/2)² + (b/2)²) = ?(a² + b²)/2
- Radius of inscribed circle = Area of rhombus / (2 × Perimeter)
- Area of circle = ? × r²
Example
This program calculates the area of a circle inscribed in a rhombus with given diagonals −
#include <stdio.h>
#include <math.h>
float calculateCircleArea(float a, float b) {
if (a <= 0 || b <= 0) {
printf("Error: Diagonal lengths must be positive<br>");
return -1;
}
float area = (M_PI * (a * b * a * b)) / (4 * (a * a + b * b));
return area;
}
int main() {
float a = 8, b = 10;
float area;
printf("Rhombus diagonals: a = %.1f, b = %.1f<br>", a, b);
area = calculateCircleArea(a, b);
if (area != -1) {
printf("Area of inscribed circle: %.4f square units<br>", area);
}
return 0;
}
Rhombus diagonals: a = 8.0, b = 10.0 Area of inscribed circle: 30.6488 square units
Key Points
- The formula uses the relationship between the rhombus diagonals and the inscribed circle radius.
- Input validation ensures positive diagonal values to avoid mathematical errors.
- The constant M_PI from math.h provides better precision than hardcoded values.
Conclusion
Calculating the area of a circle inscribed in a rhombus requires the diagonal lengths and the derived formula ?(ab)²/(4(a²+b²)). This method provides accurate results for any valid rhombus dimensions.
