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Java - Math exp(double) Method
Description
The Java Math exp(double a) returns Euler's number e raised to the power of a double value. Special cases:
If the argument is NaN, the result is NaN.
If the argument is positive infinity, then the result is positive infinity.
If the argument is negative infinity, then the result is positive zero.
The computed result must be within 1 ulp of the exact result. Results must be semi-monotonic.
Declaration
Following is the declaration for java.lang.Math.exp() method
public static double exp(double a)
Parameters
a − the exponent to raise e to.
Return Value
This method returns the value ea, where e is the base of the natural logarithms.
Exception
NA
Getting Euler's Number e Raised to the Power of a Positive Double Value Example
The following example shows the usage of Math exp() method.
package com.tutorialspoint; public class MathDemo { public static void main(String[] args) { // get a double number double x = 0.5; // print e raised at x System.out.println("Math.exp(" + x + ")=" + Math.exp(x)); } }
Output
Let us compile and run the above program, this will produce the following result −
Math.exp(0.5)=1.6487212707001282
Getting Euler's Number e Raised to the Power of a Zero Double Value Example
The following example shows the another usage of Math exp() method with zero value.
package com.tutorialspoint; public class MathDemo { public static void main(String[] args) { // get a double number double x = 0; // print e raised at x System.out.println("Math.exp(" + x + ")=" + Math.exp(x)); } }
Output
Let us compile and run the above program, this will produce the following result −
Math.exp(0.0)=1.0
Getting Euler's Number e Raised to the Power of a One Double Value Example
The following example shows the usage of Math exp() method with one value.
package com.tutorialspoint; public class MathDemo { public static void main(String[] args) { // get a double number double x = 1; // print e raised at x System.out.println("Math.exp(" + x + ")=" + Math.exp(x)); } }
Output
Let us compile and run the above program, this will produce the following result −
Math.exp(1.0)=2.718281828459045
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