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Java - Math hypot(double x, double y) Method
Description
The Java Math hypot(double x, double y) returns sqrt(x2 +y2) without intermediate overflow or underflow. Special cases:
If either argument is infinite, then the result is positive infinity.
If either argument is NaN and neither argument is infinite, then the result is NaN.
Declaration
Following is the declaration for java.lang.Math.hypot() method
public static double hypot(double x, double y)
Parameters
x − a value
y − a value
Return Value
This method returns sqrt(x2 +y2) without intermediate overflow or underflow
Exception
NA
Getting Square Root of a double value For Negative Value Example
The following example shows the usage of Math hypot() method.
package com.tutorialspoint; public class MathDemo { public static void main(String[] args) { // get two double numbers double x = 60984.1; double y = -497.99; // call hypot and print the result System.out.println("Math.hypot(" + x + "," + y + ")=" + Math.hypot(x, y)); } }
Output
Let us compile and run the above program, this will produce the following result −
Math.hypot(60984.1,-497.99)=60986.133234122164
Getting Square Root of a double value For Negative Zero Value Example
The following example shows the usage of Math hypot() method of zero value.
package com.tutorialspoint; public class MathDemo { public static void main(String[] args) { // get two double numbers double x = 0.0; double y = -0.0; // call hypot and print the result System.out.println("Math.hypot(" + x + "," + y + ")=" + Math.hypot(x, y)); } }
Output
Let us compile and run the above program, this will produce the following result −
Math.hypot(0.0,-0.0)=0.0
Getting Square Root of a double value For Negative One Value Example
The following example shows the usage of Math hypot() method of a 1 value.
package com.tutorialspoint; public class MathDemo { public static void main(String[] args) { // get two double numbers double x = 1.0; double y = -1.0; // call hypot and print the result System.out.println("Math.hypot(" + x + "," + y + ")=" + Math.hypot(x, y)); } }
Output
Let us compile and run the above program, this will produce the following result −
Math.hypot(1.0,-1.0)=1.4142135623730951
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