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Java - Math floor(double) Method
Description
The Java Math floor(double a) returns the largest (closest to positive infinity) double value that is less than or equal to the argument and is equal to a mathematical integer. Special cases:
If the argument value is already equal to a mathematical integer, then the result is the same as the argument.
If the argument is NaN or an infinity or positive zero or negative zero, then the result is the same as the argument.
Declaration
Following is the declaration for java.lang.Math.floor() method
public static double floor(double a)
Parameters
a − a value.
Return Value
This method returns the largest (closest to positive infinity) floating-point value that less than or equal to the argument and is equal to a mathematical integer.
Exception
NA
Getting Largest Value Less than or Equal to a Positive Value Example
The following example shows the usage of Math floor() method.
package com.tutorialspoint; public class MathDemo { public static void main(String[] args) { // get a double number double x = 10.7; // print the floor of the number System.out.println("Math.floor(" + x + ")=" + Math.floor(x)); } }
Let us compile and run the above program, this will produce the following result −
Math.floor(10.7)=10.0
Getting Largest Value Less than or Equal to a Zero Value Example
The following example shows the usage of Math floor() method of zero value.
package com.tutorialspoint; public class MathDemo { public static void main(String[] args) { // get a double number double x = 0.0; // print the floor of the number System.out.println("Math.floor(" + x + ")=" + Math.floor(x)); } }
Let us compile and run the above program, this will produce the following result −
Math.floor(0.0)=0.0
Getting Largest Value Less than or Equal to a Negative Value Example
The following example shows the usage of Math floor() method of a negative number.
package com.tutorialspoint; public class MathDemo { public static void main(String[] args) { // get a double number double x = -10.7; // print the floor of the number System.out.println("Math.floor(" + x + ")=" + Math.floor(x)); } }
Let us compile and run the above program, this will produce the following result −
Math.floor(-10.7)=-11.0
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