Write the natural numbers from 102 to 113 . What fraction of them are prime numbers?

To do:

We have to write the natural numbers from 102 to 113 and the fraction of them that are prime numbers.

Solution:  

Natural numbers from 102 to 113 are $102, 103, 104, 105, 106, 107, 108, 109, 110, 111, 112, 113$

Total number of natural numbers from 102 to 113 $= 12$

Prime numbers from 102 to 113 are $103, 107, 109, 113$

Total number of prime numbers from 102 to 113 $= 4$

Therefore,

The fraction of the numbers that are prime numbers $= \frac{4}{12}$