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Write five pairs of integers $(a,\ b)$ such that $a ÷ b=-3$. One such pair is $(6,\ -2)$ because $6 ÷ (-2) = (-3)$.
Given:
$(a\div b) = -3$
To do:
We have to find out five pairs of integers (a,b) such that $(a \div b) = -3$.
Solution:
$(a \div b) = -3$
This implies, $a=-3(b)$
If
$b=1, then\ a=-3(1)=-3$
$b=2, then\ a=-3(2)=-6$
$b=3, then\ a=-3(3)=-9$
$b=4, then\ a=-3(4)=-12$
$b=5, then\ a=-3(5)=-15$
Therefore, five pairs of integers other than $(6,-2)$ such that $a \div b = -3$ are $(-3,1), (-6,2), (-9,3), (-12,4)$ and $(-15,5)$.
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