Which of the following are APs? If they form an AP, find the common difference $d$ and write three more terms.
$-10, -6, -2, 2, …..$

Given:

Given sequence is $-10, -6, -2, 2, …..$

To do:

We have to check whether the given sequence is an AP. If it is an AP we have to find the common difference $d$ and write three more terms.

Solution:

In the given sequence,

$a_1=-10.2, a_2=-6, a_3=-2$

$a_2-a_1=-6-(-10)=-6+10=4$

$a_3-a_2=-2-(-6)=-2+6=4$

$a_2 - a_1 = a_3 - a_2$

$d=a_2 - a_1=4$

$a_5=a_4+d=2+4=6$

$a_6=a_5+d=6+4=10$

$a_7=a_6+d=10+4=14$