When a black metal compound XO is heated with a colourless gas Y2, then metal X and another compound Y2O are formed. Metal X is red-brown in colour which does not react with dilute acids at all. Gas Y2 can be prepared by the action of a dilute acid on any active metal. The compound Y2O is a liquid at room temperature which can turn anhydrous copper sulphate blue.(a) What do you think is metal X?(b) What could be gas Y2?(c) What is compound XO?(d) What is compound Y2O?(e) Write the chemical equation of the reaction which takes place on heating XO with Y2.(f) What type of chemical equation is illustrated in the above equation?
(a) Metal X could be Copper (Cu) as it is red-brown in colour and does not react with dilute acids
(b) Y2 could be Hydrogen (H2) as it is a colourless gas.
(c) The compound XO is Copper oxide (CuO) as it is a black metal compound
(d) The compound Y2O is Water (H2O).
(e) The chemical equation of the reaction which takes place on heating XO with Y2:
$CuO\ +\ H_{2} \ \rightarrow Cu\ +\ H_{2} O$
(f) It is a displacement reaction (which is also a redox reaction) as one active element displaces a less reactive element from its salt solution.
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