# Find Four points such that they form a square whose sides are parallel to x and y axes in C++

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// C++ implemenataion of the above approach #include <bits/stdc++.h> using namespace std; // Determine the largest square void findLargestSquare1(long long int points1[][2], int n1){ // Used to map to store which points exist map<pair<long long int, long long int>, int> m1; // mark the available points for (int i = 0; i < n1; i++) { m1[make_pair(points1[i][0], points1[i][1])]++; } long long int side1 = -1, x1 = -1, y1 = -1; // Shows a nested loop to choose the opposite corners of square for (int i = 0; i < n1; i++) { // Used to remove the chosen point m1[make_pair(points1[i][0], points1[i][1])]--; for (int j = 0; j < n1; j++) { // Used to remove the chosen point m1[make_pair(points1[j][0], points1[j][1])]--; // Verify if the other two points exist if (i != j && (points1[i][0]-points1[j][0]) == (points1[i][1]-points1[j][1])){ if (m1[make_pair(points1[i][0], points1[j][1])] > 0 && m1[make_pair(points1[j][0], points1[i][1])] > 0) { // So if the square is largest then store it if (side1 < abs(points1[i][0] - points1[j][0]) || (side1 == abs(points1[i][0] -points1[j][0]) && ((points1[i][0] * points1[i][0] + points1[i][1] * points1[i][1]) < (x1 * x1 + y1 * y1)))) { x1 = points1[i][0]; y1 = points1[i][1]; side1 = abs(points1[i][0] - points1[j][0]); } } } // Used to add the removed point m1[make_pair(points1[j][0], points1[j][1])]++; } // Used to add the removed point m1[make_pair(points1[i][0], points1[i][1])]++; } // Used to display the largest square if (side1 != -1) cout << "Side of the square is : " << side1 << ", \npoints of the square are " << x1 << ", " << y1 << " " << (x1 + side1) << ", " << y1 << " " << (x1) << ", " << (y1 + side1) << " " << (x1 + side1) << ", " << (y1 + side1) << endl; else cout << "No such square" << endl; } //Driver code int main(){ int n1 = 6; // given points long long int points1[n1][2]= { { 2, 2 }, { 5, 5 }, { 4, 5 }, { 5, 4 }, { 2, 5 }, { 5, 2 } }; // Determine the largest square findLargestSquare1(points1, n1); return 0; }

# Find Four points such that they form a square whose sides are parallel to x and y axes in C++ (GNU GCC v7.1.1)

Find Four points such that they form a square whose sides are parallel to x and y axes in C++ (GNU GCC v7.1.1) helps you to Edit, Run and Share your C++ Code directly from your browser. This development environment provides you version GNU GCC v7.1.1.

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