C++ program for Solving Cryptarithmetic Puzzles

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#include <iostream> #include<vector> using namespace std; vector<int> use(10); //set 1, when one character is assigned previously struct node{ char letter; int value; }; int isValid(node* nodeList, const int count, string s1, string s2, string s3){ int val1 = 0, val2 = 0, val3 = 0, m = 1, j, i; for (i = s1.length() - 1; i >= 0; i--){ //find number for first string char ch = s1[i]; for (j = 0; j < count; j++) if (nodeList[j].letter == ch) //when ch is present, break the loop break; val1 += m * nodeList[j].value; m *= 10; } m = 1; for (i = s2.length() - 1; i >= 0; i--){ //find number for second string char ch = s2[i]; for (j = 0; j < count; j++) if (nodeList[j].letter == ch) break; val2 += m * nodeList[j].value; m *= 10; } m = 1; for (i = s3.length() - 1; i >= 0; i--){ //find number for third string char ch = s3[i]; for (j = 0; j < count; j++) if (nodeList[j].letter == ch) break; val3 += m * nodeList[j].value; m *= 10; } if (val3 == (val1 + val2)) //check whether the sum is same as 3rd string or not return 1; return 0; } bool permutation(int count, node* nodeList, int n, string s1, string s2, string s3){ if (n == count - 1){ //when values are assigned for all characters for (int i = 0; i < 10; i++){ if (use[i] == 0){ // for those numbers, which are not used nodeList[n].value = i; //assign value i if (isValid(nodeList, count, s1, s2, s3) == 1){ //check validation cout << "Solution found: "; for (int j = 0; j < count; j++) //print code, which are assigned cout << " " << nodeList[j].letter << " = " << nodeList[j].value; return true; } } } return false; } for (int i = 0; i < 10; i++){ if (use[i] == 0){ // for those numbers, which are not used nodeList[n].value = i; //assign value i and mark as not available for future use use[i] = 1; if (permutation(count, nodeList, n + 1, s1, s2, s3)) //go for next characters return true; use[i] = 0; //when backtracks, make available again } } return false; } bool solvePuzzle(string s1, string s2,string s3){ int uniqueChar = 0; //Number of unique characters int len1 = s1.length(); int len2 = s2.length(); int len3 = s3.length(); vector<int> freq(26); //There are 26 different characters for (int i = 0; i < len1; i++) ++freq[s1[i] - 'A']; for (int i = 0; i < len2; i++) ++freq[s2[i] - 'A']; for (int i = 0; i < len3; i++) ++freq[s3[i] - 'A']; for (int i = 0; i < 26; i++) if (freq[i] > 0) //whose frequency is > 0, they are present uniqueChar++; if (uniqueChar > 10){ //as there are 10 digits in decimal system cout << "Invalid strings"; return 0; } node nodeList[uniqueChar]; for (int i = 0, j = 0; i < 26; i++){ //assign all characters found in three strings if (freq[i] > 0){ nodeList[j].letter = char(i + 'A'); j++; } } return permutation(uniqueChar, nodeList, 0, s1, s2, s3); } int main(){ string s1 = "BASE"; string s2 = "BALL"; string s3 = "GAMES"; if (solvePuzzle(s1, s2, s3) == false) cout << "No solution"; }

C++ program for Solving Cryptarithmetic Puzzles (GNU GCC v7.1.1)

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