The weights of 8 students in a class were measured in kgs and the results are as follows: $ 45,50, $ $ 49,39,52,47,41, $ and 49
I) What is the weight of the heaviest student?

II) What is the weight of the leanest student?

III) What is the mean weight of the class?
IV) How many students are there above the mean weight?
A) $ I=52 \mathrm{kgs}, \mathrm{II}=41 \mathrm{kgs}, \mathrm{III}=46 \mathrm{kgs}, \mathrm{IV}=5 $
B) $ I=52 \mathrm{kgs}, \mathrm{II}=39 \mathrm{kgs}, \mathrm{III}=46.5 \mathrm{kgs}, \mathrm{IV}=5 $

C) $ 1=52 \mathrm{kgs}, \mathrm{II}=39 \mathrm{kgs}, \mathrm{III}=47 \mathrm{kgs}, \mathrm{IV}=4 $

D) $ \mathrm{I}=52 \mathrm{kgs}, \mathrm{II}=39 \mathrm{kgs}, \mathrm{III}=47 \mathrm{kgs}, \mathrm{IV}=5 $


GIven:  Weights of 8 students in a class are \( 45,50, \) \( 49,39,52,47,41, 49\) 

To find:

I) What is the weight of the heaviest student?

II) What is the weight of the leanest student?

III) What is the mean weight of the class?

IV) How many students are there above the mean weight?


Solution:Arranging the data in ascending order: 39,41,45,47,49,49,50,52

  1. So 52 is the weight of heaviest student
  2. 39 is the weight of leanest student
  3. Mean Weight \( =39+41+45+47+49+49+50+\frac{52}{8}=\frac{372}{8}=46.5 \)
  4. 5 students (47,49,49,50,52) have more weight than 46.5  

Answer is B

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Updated on: 10-Oct-2022

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