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# The values of current (I) flowing through a given resistor of resistance (R), for the corresponding values of potential difference (V) across the resistor are as given below :

V (Volts) | 0.5 | 1.0 | 1.5 | 2.0 | 2.5 | 3.0 | 4.0 | 5.0 |

I (Amperes) | 0.1 | 0.2 | 0.3 | 0.4 | 0.5 | 0.6 | 0.8 | 1.0 |

**Plot a graph between current (I) and potential difference (V) and determine the resistance (R) of the resistor.**

The plot between current $(I)$ and potential difference $(V)$ is given as-

Resistance of the resistor (R) = Slope of the above graph

Choose any two points P and Q on the graph,

Resistnce of the resistor (R) = Slope of line **$PQ=\frac{4-1}{0.8-02}=\frac{3}{0.6}=\frac{30}{6}=5\Omega $**

__Alternate Solution__

We know that-

**$R=\frac{\Delta V}{\Delta I}$**

Where,

**$R$ **= Resistance

**$V$** = Potential difference or Voltage

**$I$ **= Current

**$\Delta $** = shows change

Putting the given values we get-

**$R=\frac{3-2}{0.6-0.4}$**

**$R=\frac{1}{0.2}$**

**$R=\frac{10}{2}$**

**$R=5\Omega $**

**NOTE: For every point on the graph, the resistance will remain the same.**

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