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# The paint in a certain container is sufficient to paint an area equal to $ 9.375 \mathrm{~m}^{2} $. How many bricks of dimensions $ 22.5 \mathrm{~cm} \times 10 \mathrm{~cm} \times 7.5 \mathrm{~cm} $ can be painted out of this container?

Given:

The paint in a certain container is sufficient to paint an area equal to $9.375\ m^2$.

The dimensions of each brick is $22.5\ cm \times 10\ cm \times 7.5\ cm$.

To do:

We have to find the number of bricks that can be painted out of the container.

Solution:

Area of the place for painting $= 9.375\ m^2$

Dimension of each brick $= 22.5\ cm \times 10\ cm \times 7.5\ cm$

Therefore,

Surface area of each brick $= 2 (lb + bh + lh)$

$= 2(22.5 \times 10 + 10 \times 7.5 + 7.5 \times 22.5)$

$= 2(225 + 75 + 168.75)$

$= 2 \times 468.75$

$= 937.5\ cm^2$

This implies,

Number of bricks that can be painted $=\frac{\text { Total area }}{\text { Area of one brick }}$

$=\frac{9.375 \times 100 \times 100}{937.5}$

$=\frac{937.5 \times 100}{937.5}$

$=100$ bricks

Therefore, the number of bricks that can be painted out of the container is $100$ bricks.

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