The distance of the point $ P(2,3) $ from the $ x $-axis is
(A) 2
(B) 3
(C) 1
(D) 5
Given:
Point $P (2,\ 3)$.
To do:
We have to find the distance of the point $P (2,\ 3)$ from the $x-axis$.
Solution:
As given, $P (2,\ 3)$,
Co-ordinate of $x-axis=( 2,\ 0)$
Therefore, distance of the point $P (2,\ 3)$ from the $x-axis=\sqrt{( 2-2)^2+( 0-3)^2}$
$=\sqrt{0+9}$
$=\sqrt{9}$
$=3\ units$
Thus, the distance of the point $P (2,\ 3)$ from the $x-axis$ is $3\ units$.
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