The distance between the school and a student's house is $ 1 \mathrm{~km} 875 \mathrm{~m} $. Everyday she walks both ways. Find the total distance covered by her in six days.
Given:
The distance between the school and a student's house is $1\ km\ 875\ m$. Everyday she walks both ways.
To do:
We have to find the total distance covered by her in six days.
Solution:
Distance between the school and student's house$=1\ km\ 875\ m$
$=1000\ m+875\ m$ [$\because 1\ km=1000\ m$]
$=1875\ m$
$\because$ The student walks both ways, then
The distance covered by the student in a day$=2\times 1875$
$=3750\ m$
Therefore, the distance covered by the student in six days $=6\times 3750$
$=22500\ m$
$=\frac{22500}{1000}\ km$
$=22km\ 500\ m$
Therefore, the distance covered by the student in six days is $22\ km\ 500\ m$.
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