# Sweety runs around a square park of side $75 \mathrm{~m}$. Bulbul runs around a rectangular park with length $60 \mathrm{~m}$ and breadth $45 \mathrm{~m}$. Who covers less distance?

#### Complete Python Prime Pack

9 Courses     2 eBooks

#### Artificial Intelligence & Machine Learning Prime Pack

6 Courses     1 eBooks

#### Java Prime Pack

9 Courses     2 eBooks

Given:

Sweety runs around the square park of side $75\ m$. Bulbul runs around the rectangular park with length $60\ m$ and breadth $45\ m$.

To do:

We have to find that who among them covers less distance.

Solution:

The side of square park $= 75\ m$

We know that,

The perimeter of a square with side $a$ is $4a$.

Therefore,

The perimeter of square park $= 4\times$ each side of the square park

$= 4\times75$

$= 300\ m$

The distance covered by Sweety is $300\ m$.

The length of the rectangular park $=175\ m$

The breadth of the rectangular park $=125\ m$

We know that,

The perimeter of a rectangle of length $l$ and breadth $b$ is $2(l+b)$

Therefore,

The perimeter of the rectangular park $= 2\times(60+45)$

$= 2\times105$

$= 210\ m$

The distance covered by Bulbul is $210\ m$.

Hence, Bulbul covers less distance than Sweety.

Updated on 10-Oct-2022 13:36:27