Sweety runs around a square park of side $ 75 \mathrm{~m} $. Bulbul runs around a rectangular park with length $ 60 \mathrm{~m} $ and breadth $ 45 \mathrm{~m} $. Who covers less distance?

Given:

Sweety runs around the square park of side $75\ m$. Bulbul runs around the rectangular park with length $60\ m$ and breadth $45\ m$.

To do:

We have to find that who among them covers less distance.

Solution:

 The side of square park $ = 75\ m$

We know that,

The perimeter of a square with side $a$ is $4a$.

Therefore,

The perimeter of square park $ = 4\times$ each side of the square park

$= 4\times75$

$= 300\ m$

The distance covered by Sweety is $300\ m$.

The length of the rectangular park $ =175\ m$

The breadth of the rectangular park $ =125\ m$

We know that,

The perimeter of a rectangle of length $l$ and breadth $b$ is $2(l+b)$

Therefore,

The perimeter of the rectangular park $ = 2\times(60+45)$ 

$= 2\times105$

$= 210\ m$

The distance covered by Bulbul is $210\ m$.

Hence, Bulbul covers less distance than Sweety.

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Updated on: 10-Oct-2022

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