State whether the following statements are true or false. Justify your answer.
A circle has its centre at the origin and a point $ P(5,0) $ lies on it. The point $ \mathrm{Q}(6,8) $ lies outside the circle.
Given:
A circle has its centre at the origin and a point \( P(5,0) \) lies on it. The point \( \mathrm{Q}(6,8) \) lies outside the circle.
To do:
We have to find whether the given statement is true or false.
Solution:
The distance between origin $O(0,0)$ and $P(5,0)$ is,
$OP=\sqrt{(5-0)^{2}+(0-0)^{2}}$
$=\sqrt{5^{2}}$
$=5$
This implies,
The radius of the circle is 5 units.
If the point \( \mathrm{Q}(6,8) \) lies outside the circle, then the distance between the origin and point $Q$ is greater than the radius of the circle.
The distance between $O(0,0)$ and $Q(6,8)$ is,
$OQ=\sqrt{(6-0)^{2}+(8-0)^{2}}$
$=\sqrt{6^{2}+8^{2}}$
$=\sqrt{36+64}$
$=\sqrt{100}$
$=10$
$OQ=10>5$
The distance between $O(0,0)$ and $Q(6,8)$ is greater than the radius of the circle.
Hence, the point \( \mathrm{Q}(6,8) \) lies outside the circle.
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