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# Solve the following riddles, you may yourself construct such riddles.

Who am I?

**(i)** Go round a square

Counting every corner

Thrice and no more!

Add the count to me

To get exactly thirty four!

**(ii)** For each day of the week

Make an upcount from me

If you make no mistake

You will get twenty three!

**(iii)** I am a special number

Take away from me a six!

A whole cricket team

You will still be able to fix!

**(iv)** Tell me who I am

I shall give a pretty clue!

You will get me back

If you take me out of twenty two!

To do:

We have to solve the given riddles.

Solutions:

(i) Number of corners in a square $=4$

Thrice the number of corners in the square $= 3 \times 4$

$= 12$

When 12 is added to the number it becomes 34.

This implies,

The number is the difference between 34 and 12

$34 - 12 = 22$

(ii) The result is 23 when the old number is up counted on Sunday.

The result is 22 when the old number is up counted on Saturday.

The result is 21 when the old number is up counted on Friday.

The result is 20 when the old number is up counted on Thursday

The result is 19 when the old number is up counted on Wednesday

The result is 18 when the old number is up counted on Tuesday

The result is 17 when the old number is up counted on Monday

`Therefore, the number taken at the start $=17 - 1 = 16$

(iii) We know that,

There are 11 players in a cricket team

If 6 is subtracted from the required number, the result will be 11

This implies,

$11 + 6 = 17$

Therefore, the number is 17

(iv) The required number is such that if it is subtracted from 22 the result is the number itself.

$22-x=x$

$22=2x$

$x=\frac{22}{2}$

$x=11$

The required number is 11.

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