Solve the following linear equation.
\( \frac{x}{2}-\frac{1}{5}=\frac{x}{3}+\frac{1}{4} \).
Given:
$\frac{x}{2}-\frac{1}{5}=\frac{x}{3}+\frac{1}{4}$.
To do:
We have to solve the given linear equation.
Solution:
$\frac{x}{2} - \frac{1}{5} = \frac{x}{3}+\frac{1}{4}$
This implies,
$\frac{x}{2} -\frac{x}{3} =\frac{1}{4} +\frac{1}{5}$
$\frac{3\times x-2\times x}{6}=\frac{1\times5+1\times4}{20}$
$\frac{3x-2x}{6}=\frac{5+4}{20}$
$\frac{x}{6}=\frac{9}{20}$
$x=6\times\frac{9}{20}$
$x=\frac{27}{10}$
The value of $x$ is $\frac{27}{10}$.
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