Solve the following equations by trial and error method:
$(i).\ 5p+2=17$
$(ii).\ 3m-14=4$

Given:

Given equations are

(i) $5p+2=17$

(ii) $3m-14=4$

To do:

We have to solve the given equations by trial and error method.

Solution:

(i) $5p+2=17$

$5p+2=$L.H.S

By putting, $p=0$,

$5(0)+2=2$

$≠17$

By putting, $p=1$,

$5(1)+2=7$

$≠17$

By putting, $p=2$,

$5(2)+2=12$

$≠$R.H.S

By putting, $p=3$,

$5(3)+2=17$

$=$R.H.S

Therefore, $p=3$ is a solution of the equation.

(ii) $3m-14=4$

$3m-14=$L.H.S

By putting, $m=5$,

$3(5)-14=1$

$≠6$

By putting, $m=6$,

$3(6)-14=4=$R.H.S.

Therefore, $m=6$ is a solution of the equation.

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Updated on: 10-Oct-2022

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