Solve the following equations and check your results.
$ 8 x+4=3(x-1)+7 $.

Given:

\( 8 x+4=3(x-1)+7 \)

To do:
 We have to solve the given equation and check the result.

Solution:

$8 x+4=3(x-1)+7$

$8x+4=3x-3+7$

$8x-3x=4-4$

$5x=0$

$x=\frac{0}{5}$

$x=0$

Substituting the value of $x$ in LHS, we get,

$8x+4=8(0)+4$

$=0+4$

$=4$

Substituting the value of $x$ in RHS, we get,

$3(x-1)+7=3(0-1)+7$

$=3(-1)+7$

$=-3+7$

$=4$

LHS $=$ RHS

The value of $x$ is $0$.