Solve the following equations and check your results.
$ 4 z+3=6+2 z $.

Given:

\( 4 z+3=6+2 z \)

To do:
 We have to solve the given equation and check the result.

Solution:

$4z+3=6+2z$

$4z-2z=6-3$

$2z=3$

$z=\frac{3}{2}$

Substituting the value of $z$ in LHS, we get,

$4z+3=4(\frac{3}{2})+3$

$=2(3)+3$

$=6+3$

$=9$

Substituting the value of $z$ in RHS, we get,

$6+2z=6+2(\frac{3}{2})$

$=6+3$

$=9$

LHS $=$ RHS

The value of $z$ is $\frac{3}{2}$.