Solve the following equations and check your results.
$ 2 y+\frac{5}{3}=\frac{26}{3}-y $.

Given:

\( 2 y+\frac{5}{3}=\frac{26}{3}-y \)

To do:
 We have to solve the given equation and check the result.

Solution:

$2 y+\frac{5}{3}=\frac{26}{3}-y$

$2y+y=\frac{26}{3}-\frac{5}{3}$

$3y=\frac{26-5}{3}$

$3y=\frac{21}{3}$

$3y=7$

$y=\frac{7}{3}$

Substituting the value of $y$ in LHS, we get,

$2y+\frac{5}{3}=2(\frac{7}{3})+\frac{5}{3}$

$=\frac{14}{3}+\frac{5}{3}$

$=\frac{14+5}{3}$

$=\frac{19}{3}$

Substituting the value of $y$ in RHS, we get,

$\frac{26}{3}-y=\frac{26}{3}-\frac{7}{3}$

$=\frac{26-7}{3}$

$=\frac{19}{3}$

LHS $=$ RHS

The value of $y$ is $\frac{7}{3}$.    

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Updated on: 10-Oct-2022

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