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# Simplify and solve the following linear equations.

$ 15(y-4)-2(y-9)+5(y+6)=0 $.

Given:

$15(y-4)-2(y-9)+5(y+6)=0$.

To do:

We have to solve the given linear equation.

Solution:

$15(y-4)-2(y-9)+5(y+6)=0$

This implies,

$15(y)-15(4)-2(y)-2(-9)+5(y)+5(6)=0$

$15y-60-2y+18+5y+30=0$

$18y-12=0$

$18y=12$

$y =\frac{12}{18}$

$y = \frac{2}{3}$

The value of $y$ is $\frac{2}{3}$.

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