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Simplify and solve the following linear equations.
$ 15(y-4)-2(y-9)+5(y+6)=0 $.
Given:
$15(y-4)-2(y-9)+5(y+6)=0$.
To do:
We have to solve the given linear equation.
Solution:
$15(y-4)-2(y-9)+5(y+6)=0$
This implies,
$15(y)-15(4)-2(y)-2(-9)+5(y)+5(6)=0$
$15y-60-2y+18+5y+30=0$
$18y-12=0$
$18y=12$
$y =\frac{12}{18}$
$y = \frac{2}{3}$
The value of $y$ is $\frac{2}{3}$.
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