Several electric bulbs designed to be used on a $220\ V$ electric supply line, are rated $10\ W$. How many lamps can be connected in parallel with each other across the two wires of a $220\ V$ line if the maximum allowable current is $5\ A$?
Given: Two wires of a $220\ V$ line with the maximum allowable current $5\ A$. And a bulb designed to be used on a $220\ V$ electric supply line, is rated $10\ W$.
To do:
To find the number of bulbs that can be connected in parallel with each other across the given two wires.
Solution:
Given,
Potential Difference, V = 220 V
The power rating of each bulb, P = 10 W
Total current, I = 5 A
Let the number of lamps in parallel be n.
First, we will find the resistance of each bulb.
We know that,
$P=V\times I\phantom{\rule{0ex}{0ex}}$
$P=V\times \frac{V}{R}$ $(\because\ V=I\times R,\ I=\frac{V}{R})$
$P=\frac{{V}^{2}}{R}\phantom{\rule{0ex}{0ex}}$
$R=\frac{{V}^{2}}{P}\phantom{\rule{0ex}{0ex}}$
$R=\frac{(220{)}^{2}}{10}\phantom{\rule{0ex}{0ex}}$
$R=\frac{48400}{10}\phantom{\rule{0ex}{0ex}}$
$R=4840\Omega$
Resistance of 1 bulb = $4840\Omega$
For a flow of 5A current, we need to find the equivalent resistance of the circuit.
By Ohm's Law
$V=I\times {R}_{E}\phantom{\rule{0ex}{0ex}}$
${R}_{E}=\frac{V}{I}\phantom{\rule{0ex}{0ex}}$
${R}_{E}=\frac{220}{5}\phantom{\rule{0ex}{0ex}}$
${R}_{E}=44\Omega$
We know that,
In parallel combination, the equivalent resistance is given by-
$\frac{1}{{\mathrm{R}}_{\mathrm{p}}}=\frac{1}{{\mathrm{R}}_{1}}+\frac{1}{{\mathrm{R}}_{2}}+\frac{1}{{\mathrm{R}}_{3}}+.......$
$\therefore \frac{1}{{\mathrm{R}}_{\mathrm{E}}}=\frac{1}{\mathrm{R}}+\frac{1}{\mathrm{R}}+\frac{1}{\mathrm{R}}+.......$ (n times)
$\frac{1}{{\mathrm{R}}_{\mathrm{E}}}=n\times \frac{1}{\mathrm{R}}\phantom{\rule{0ex}{0ex}}$
$\frac{1}{44}=n\times \frac{1}{4840}\phantom{\rule{0ex}{0ex}}$
$\therefore \mathrm{n}=\frac{4840}{44}\phantom{\rule{0ex}{0ex}}$
$\mathrm{n}=\frac{1210}{11}\phantom{\rule{0ex}{0ex}}$
$\mathrm{n}=110\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}$
So, 110 lamps can be connected in parallel.
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